A charged particle with velocity 2×10³ m/s passes undeflected through electric and magnetic field intensity. Magnetic field is 1.5 T. The electric field intensity would be

• 2×10³ N/C

• 1.5×10³ N/C

• 3×10³ N/C

• 4/3×10^–3 N/C

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NGSS.HS-PS2-4

NGSS.HS-PS2-5

NGSS.HS-PS3-5

An electron of mass m is accelerated through a potential difference of V and then it enters a magnetic field of induction B normal to the lines. Then the radius of the circular path is

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NGSS.HS-PS2-5

Two current carrying conductors are placed parallel as shown in figure. Which point will experience the strong magnetic field?

• X

• Both experience same magnetic field

• Y

• None of these

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NGSS.HS-PS2-5

The acceleration of an electron of mass m and charge e, moving with uniform speed v at right angles to a magnetic field of flux density B, is give by

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NGSS.HS-PS2-1

NGSS.HS-PS2-5

NGSS.HS-PS3-5

The radius of curvature of the path of the charged particle in a uniform magnetic field is directly proportional to

• The energy of the particle

• The intensity of the field

• The momentum of the particle

• The charge on the particle

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NGSS.HS-PS2-2

NGSS.HS-PS2-5

NGSS.HS-PS3-5

Direction of magnetic flux is

• Normal to the surface

• Parallel to the surface

• At any angle

• No direction

In step up transformer, voltage in the secondary increases and power in secondary

• Remain same

• Increases because current decreases

• Decreases because voltage increases

• May increases if voltage remain same

The magnetic flux linked with a coil is changed from 1 weber to 0.1 weber in 0.1 sec. the induced e.m.f is:

• 9V

• 0.009V

• 10V

• 1/9V

Tags

NGSS.HS-PS2-5

NGSS.HS-PS3-5

Laminated core in a transformer is used to reduce

• Eddy current losses

• Hysteresis losses

• Iron losses

• Heat losses due to resistance

A transformer steps 220 V to 40 voltages. If the secondary turns are 40 and primary turns are:

• 20

• 40

• 120

• 220

Tags

NGSS.HS-PS3-5