Factoring and Solving Quadratic Equations

• A.

  Divide both sides f the equation by 3.

• B.

  Take the square root of both sides of the equation.

• C.

  Subtract 12 from both sides of the equation.

• D.

  Find two values with a sum of 5 and a product of 12.

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.HSA-REI.B.4B

• A.

  x = 7 only

• B.

  x = 0 only

• C.

  x = 0 and 7

• D.

  There is no real answer for this equation.

Tags

CCSS.HSA-REI.B.4B

• A.

  Yes, she factored correctly and then used the zero product property

• B.

  No, she didn't factor correctly so the rest of her work is wrong.

• C.

  No, she did not set the equation equal to zero before factoring.

• D.

  Yes, she answered it correctly.

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x + 2)(x - 3) = 0

• A.

  { 2, 3 }

• B.

  { -2, -3 }

• C.

  { 2, 3 }

• D.

  { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

Factor: x² – 5x – 24

• A.

  (x - 5)(x + 19)

• B.

  (x - 8)(x + 3)

• C.

  (x - 3)(x + 8)

• D.

  (x - 19)(x + 5)

Find all the solutions for x when

x² + 9x - 36 = 0

• A.

  (x + 12)(x - 3)

• B.

  x = 12 and x = -3

• C.

  x = -12 and x = 3

• D.

  (x - 9)(x - 4)

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.8.EE.A.2

Tags

CCSS.HSA-REI.B.4B

Solve 2x² - 7x + 6 = 0 by factoring

• x = -3/2 and x = -2

• x = -3 and x = -2

• x = 3 and x = 2

• x = 3/2 and x = 2

Tags

CCSS.HSA-REI.B.4B