
Problems on Ages
Quiz
•
Mathematics
•
8th Grade - University
•
Practice Problem
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Medium
Manish R
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Father is four times the age of his daughter. If after 5 years, he would be threee times of daughter’s age, then further after 5 years, how many times he would be of his daughter’s age?
1.5 times
2 times
2.5 times
3 times
Answer explanation
Let father's age = x
Daughter's age = y
x = 4y
x + 5 = 3(y + 5).
4y+5 = 3y + 15
y = 10
Hence present age of daughter is 10 years and present age of father is 40 years.
So after 5 + 5 = 10 years, daughter age would be 20 years and father’s age would be 50 years.
Hence father would be 50/20 = 2.5 times of daughter’s age.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is Aman's present age, if after 20 years his age will be 10 times his age 10 years back?
13.3
6.7
10
7.7
Answer explanation
Aman's present age be x
before 10 years = x - 10
after 20 years = (x + 20)
x + 20 = 10 (x – 10)
x + 20 = 10x – 100
9x = 120,
x = 13.3 years
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Nisha is 15 years elder to Romi. If 5 years ago, Nisha was 3 times as old as Romi, then find Nisha’s present age.
32.5
27.5
25
24.9
Answer explanation
Let
Age of Nisha be x
age of Romi be y
x = (y + 15).
5 years ago x - 5 = 3(y– 5).
(y + 15) – 5 = 3 (y – 5)
(y + 10) = (3y – 15)
2y = 25 ⇒ y = 12.5
Romi's age = 12.5 years
Nisha's age x = (y + 15) = (12.5 + 15) = 27.5
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
One year ago, the ratio of Honey and Piyush ages was 2: 3 respectively. After five years from now, this ratio becomes 4: 5. How old is Piyush now?
5
25
10
15
Answer explanation
Age ratio of H : P = 2: 3
H = 2x and P= 3x
One year ago, their age was 2x and 3x.
Now, H = 2x +1 and P = 3x +1
After 5 years, H = (2x +1) + 5 = (2x + 6)
P= (3x +1) + 5 = (3x + 6)
After 5 years, this ratio becomes 4: 5. Therefore,
(2x+6) / (3x+6) = 4/5
10x + 30 = 12x + 24
⇒ x = 3
P = (3x + 1) = (3x 3 + 1) = 10 years
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Ten years ago, the age of mother was three times the age of her son. After ten years, mother’s age will be twice that of his son. Find the ratio of their present ages.
11:7
9:5
7:9
7:3
Answer explanation
At present age of Mother be x and
Son's age be y.
10 years ago, x-10 = 3(y-10)
x - 10 = 3y -30
x - 3y = -20 ....... (1)
After ten years, x+10 = 2 (y+10)
x+10 = 2y +20
x - 2y = 10........ (2)
Solving the equation 1 & 2
, we get y = 30
and x = 70
x:y = 70: 30 = 7: 3.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Saransh is 50 years old and Nazma is 40 years old. How long ago was the ratio of their ages 3:2?
20
30
40
25
Answer explanation
x years ago: S = (50 – x) and N= (40 – x)
Given, the ratio of their ages was 3:2
(50-x) / (40-x) = 3/2
Solving, we get: x = 20
Therefore, the answer is 20 years.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The ratio of the present ages of Pranav and Qureshi is 4:5. Five years ago, the ratio of their ages was 7:9. Find their present ages?
18,25
40,50
25,35
20,30
Answer explanation
Their present ages be 4X and 5X.
5 years ago, the ratio of their ages was 7:9, then (4X - 5) /( 5X - 5) = 7/9
X = 45 - 35 ⇒ X = 10.
Their present ages are: 40, 50.
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