
Kinematics Review
Authored by Desiree Boyett
Science
11th Grade
NGSS covered
Used 6+ times

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27 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 5 pts
A quantity that is has magnitude and direction is referred to as a
Tags
NGSS.MS-PS2-2
NGSS.MS-PS2-4
NGSS.MS-PS2-5
2.
MULTIPLE CHOICE QUESTION
30 sec • 5 pts
You run from your house to a friend's house that is 3 km away. You then walk home. The distance you traveled is 6 km. What is your displacement?
3.
MULTIPLE CHOICE QUESTION
1 min • 5 pts
A hummingbird averages a speed of about 45 km/hour (Cool facts: They visit up to 1000 flowers per day, and reach maximum speed, while diving, up to 160 km/hour!). Ruby-throated hummingbirds take a non-stop trip across Gulf of Mexico in which they fly for 18 hours straight! How far is the trip across the Gulf of Mexico at their average speed?
4.
MULTIPLE CHOICE QUESTION
30 sec • 5 pts
A car is traveling south for 250 meters over the course of 100 seconds. What was the car's average velocity?
0.4 m/s south
0.4 m/s
2.5 m/s
2.5 m/s south
5.
MULTIPLE CHOICE QUESTION
30 sec • 5 pts
A car is travelling along the road. It starts at 10 m/s and accelerates to a velocity of 25 m/s. It speeds up over a period of 5 seconds. What is the acceleration?
Answer explanation
Our knowns are:
Vi = 10m/s; Vf = 25m/s; t = 5s
We are looking for acceleration (a)
Our formula is:
Vf = Vi + at
25m/s = 10m/s + a(5s)
-10m/s -10m/s
15 = a(5s)
divide both sides by 5s
t = 3m/s^2
6.
MULTIPLE CHOICE QUESTION
30 sec • 5 pts
A car is travelling along the road. It starts at 10 m/s and accelerates to a velocity of 25 m/s. It speeds up over a period of 5 seconds. What distance does it travel during this time?
62.5 m
77.5 m
82.5 m
87.5 m
Answer explanation
Our knowns are
Vi =10 m/s; Vf = 25 m/s; t = 5s
We are looking for distance. In order to find distance, we can first find acceleration.
Our formula is:
a = change in velocity/t
a = (25 m/s - 10 m/s)/5s
a = (15)/5
a = 3 m/s^2
Now distance:
d = vit + 1/2at^2
d = (10m/s)(5s) + (1/2)(3m/s^2)(5s)^2
d = 50 + 37.5
d = 87.5m
Tags
NGSS.MS-PS2-2
7.
MULTIPLE CHOICE QUESTION
30 sec • 5 pts
A bicyclist is travelling along a bike path in the park at a constant velocity of 4 m/s. A deer darts in front of the bicyclist and they hit the brakes. The brakes decelerate the bike at -2 m/s^2.
How long does it take the bicyclist to stop?
0.5s
1.0s
1.5s
2.0s
Answer explanation
Our knowns are:
Vi = 4 m/s, Vf = 0 m/s,
a = -2m/s^2
We are looking for time t
Our equation is
Vf = Vi + at
0 m/s = 4 m/s + -2m/s^2 (t)
add + 2 m/s^2 (t) to both sides
2 m/s^2(t) = 4 m/s
Divide both sides by 2 m/s^2
t = 2s
Tags
NGSS.MS-PS2-2
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