Kinematics Review

Kinematics Review

11th Grade

27 Qs

quiz-placeholder

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Kinematics Review

Kinematics Review

Assessment

Quiz

Science

11th Grade

Medium

NGSS
MS-PS2-2, MS-PS3-1, MS-PS2-4

+1

Standards-aligned

Created by

Desiree Boyett

Used 4+ times

FREE Resource

27 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

A quantity that is has magnitude and  direction is referred to as a
vector quantity
scalar quantity

Tags

NGSS.MS-PS2-2

NGSS.MS-PS2-4

NGSS.MS-PS2-5

2.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

You run from your house to a friend's house that is 3 km away. You then walk home. The distance you traveled is 6 km. What is your displacement? 
6  km
0 km

3.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

A hummingbird averages a speed of about 45 km/hour (Cool facts: They visit up to 1000 flowers per day, and reach maximum speed, while diving, up to 160 km/hour!). Ruby-throated hummingbirds take a non-stop trip across Gulf of Mexico in which they fly for 18 hours straight! How far is the trip across the Gulf of Mexico at their average speed?
810 km
2.5 km
3.6 km
360 km

4.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

Media Image

A car is traveling south for 250 meters over the course of 100 seconds. What was the car's average velocity?

0.4 m/s south

0.4 m/s

2.5 m/s

2.5 m/s south

5.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

A car is travelling along the road. It starts at 10 m/s and accelerates to a velocity of 25 m/s. It speeds up over a period of 5 seconds. What is the acceleration?

Answer explanation

Our knowns are:

Vi = 10m/s; Vf = 25m/s; t = 5s

We are looking for acceleration (a)

Our formula is:

Vf = Vi + at

25m/s = 10m/s + a(5s)

-10m/s -10m/s

15 = a(5s)

divide both sides by 5s

t = 3m/s^2

6.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

A car is travelling along the road. It starts at 10 m/s and accelerates to a velocity of 25 m/s. It speeds up over a period of 5 seconds. What distance does it travel during this time?

62.5 m

77.5 m

82.5 m

87.5 m

Answer explanation

Our knowns are

Vi =10 m/s; Vf = 25 m/s; t = 5s

We are looking for distance. In order to find distance, we can first find acceleration.

Our formula is:

a = change in velocity/t

a = (25 m/s - 10 m/s)/5s

a = (15)/5

a = 3 m/s^2

Now distance:

d = vit + 1/2at^2

d = (10m/s)(5s) + (1/2)(3m/s^2)(5s)^2

d = 50 + 37.5

d = 87.5m

Tags

NGSS.MS-PS2-2

7.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

A bicyclist is travelling along a bike path in the park at a constant velocity of 4 m/s. A deer darts in front of the bicyclist and they hit the brakes. The brakes decelerate the bike at -2 m/s^2.

How long does it take the bicyclist to stop?

0.5s

1.0s

1.5s

2.0s

Answer explanation

Our knowns are:

Vi = 4 m/s, Vf = 0 m/s,

a = -2m/s^2

We are looking for time t

Our equation is

Vf = Vi + at

0 m/s = 4 m/s + -2m/s^2 (t)

add + 2 m/s^2 (t) to both sides

2 m/s^2(t) = 4 m/s

Divide both sides by 2 m/s^2

t = 2s

Tags

NGSS.MS-PS2-2

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