Persamaan Lingkaran

$$\left(x-3\right)^2+\left(y-1\right)^2=81$$

$$\left(x-3\right)^2+\left(y+1\right)^2=81$$

$$\left(x+3\right)^2+\left(y-1\right)^2=81$$

$$(x-3)^2+(y+1)^2=18$$

$$(x-3)^2+(y-1)^2=18$$

(x-7)^2+(x-6)^2=25

(x+7)^2+(x-6)^2=25

(x-7)^2+(x+6)^2=25

$$(x-2)^2+(y-9)^2=10$$

$$(x-2)^2+(y+9)^2=10$$

$$(x+2)^2+(y-9)^2=100$$

$$(x-2)^2+(y-9)^2=100$$

$$(x-2)^2+(y+9)^2=100$$

$$(x-3)^2+(y-1)^2=13$$

$$(x+3)^2+(y-1)^2=17$$

$$(x-3)^2+(y+1)^2=13$$

$$(x-3)^2+(y-1)^2=17$$

$$(x-3)^2+(y+1)^2=17$$

$$(x-5)^2+(y-7)^2=45$$

$$(x-5)^2+(y+7)^2=45$$

$$(x+5)^2+(y-7)^2=45$$

$$(x-5)^2+(y-7)^2=5$$

$$(x-5)^2+(y+7)^2=5$$

$$(x-3)^2+(y-5)^2=13$$

$$(x-3)^2+(y+5)^2=65$$

$$(x+3)^2+(y+5)^2=65$$

$$(x+3)^2+(y+5)^2=13$$

$$(x-3)^2+(y+5)^2=13$$