CH4   +   4 Cl2   →   CCl4  +  4 HCl

If we have 437.496 g of HCl come out of the reaction, how many moles of HCl were there?

• 1

• 3

• 12

• 6

Tags

NGSS.HS-PS1-7

Using the following equation:
4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(l)
How many grams of oxygen gas are needed to react with 56.8 grams of ammonia?

• 45.08 g O₂
• 133.33 g O₂
• 260.77 g O₂
• 75.92 g O₂

Tags

NGSS.HS-PS1-7

Use the following equation:
NaIO₃(aq) + 6HI(aq) --> 3I₂(s) + NaI(aq) + 3H₂O(l)
How many moles of iodine can be made from 6.55 moles of NaIO₃?

• 4.55 moles I₂
• 23.18 moles I₂
• 19.65 moles I₂
• 34.99 moles I₂

Tags

NGSS.HS-PS1-7

 CaC₂(s) + 2H₂O(l)   -->   C₂H₂(g)   + Ca(OH)₂(aq)
how many grams of Ca(OH)₂ would be formed with 3.20 moles of CaC₂?

• 119 g
• 21.2 g
• 114 g
• 237 g

Tags

NGSS.HS-PS1-7

Mg(s) + 2 HCl(aq)  -->  MgCl₂(aq)   + H₂(g)
How many moles of HCl are consumed in the production of 7.5 moles of MgCl₂?

• 3.8 moles
• 15 moles
• 7.5 moles
• 23 moles

Tags

NGSS.HS-PS1-7

2Al + 3H₂SO₄ -> Al₂(SO₄)₃ + 3H₂
How many grams of aluminum sulfate would be formed if 250g H₂SO₄ completely reacted with aluminum?

• 0.85 g
• 290 g
• 450 g
• 870 g

Tags

NGSS.HS-PS1-7

4 Al + 3 O₂ –> 2 Al₂O₃  How much aluminum would be needed to completely react with 45 grams of O₂?

• 1.05 moles
• 3.75 moles
• 1.875 grams
• 1.875 moles

Tags

NGSS.HS-PS1-7

B₂H₆ + 3O₂ -->2 HBO₂ + 2 H₂O
 What mass of O₂ will be needed to burn 36.1 g of B₂H₆?

• 13.8 g O₂
• 3.86 mol of O₂
• 124 g O₂

Tags

NGSS.HS-PS1-7

2 NaClO₃ (s) --> 2NaCl (s) +3 O₂ (g)  
12.00 moles of NaClO₃ will produce how many grams of O₂?

• 256 g of O₂
• 576 g of O₂
• 288 g O₂

2H₂   +   O₂  →  2H₂O
How many moles of water can be produced if 8 moles H₂ are used?

• 4 moles
• 8 moles
• 16 moles
• 2 moles

Tags

NGSS.HS-PS1-7