Alg 6.5 Coin Problems

Alg 6.5 Coin Problems

11th - 12th Grade

8 Qs

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Alg 6.5 Coin Problems

Alg 6.5 Coin Problems

Assessment

Quiz

Science

11th - 12th Grade

Practice Problem

Medium

Created by

Rebecca Bankwitz

Used 14+ times

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8 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

If Jane has 36 coins totaling $3.00, and the coins are all nickels and quarters, how many of each coin does she have?


Which equations can you set up for this problem? Select 2

N + Q = 3.00

N + Q = 36

0.05N + 0.25Q = 36

0.5N + 0.25Q = 3.00

0.05N + 0.25Q = 3.00

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Caitlin won a bag full of money! She has 49 bills in all. She counts $1430. There are twenty dollar bills and fifty dollar bills. How many of each bill does Caitlin have? Which system best represents the situation?

x + y = 1430

20x + 50y = 49

x + y = 49

10x + 5y = 1430

x + y = 49

20x + 50y = 1430

x + y = 49

x + y = 1430

3.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

In a child’s bank are 11 coins that have a value of $1.85. The coins are either quarters and dimes.

Which equations can you set up for this problem? Select 2

Q + D = 11

25Q + 10D = 185

25Q + 10D = 11

Q + D = 185

4.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

The number of Lily's nickels is three times as much as her quarters. The total value of her coins is $3.20. Which two equations represent this system of equations?

N = 3Q

Q = 3N

5N + 25Q = $3.20

5N + 25Q = 320

.5 + .25Q = 320

5.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Ben has $11.80 in nickels and dimes. Ben has 8 more nickels than dimes. Which two equations represent this situation?

D = N + 8

10N + 5D = 1180

5N + 10D = 1180

N = D + 8

5N + 10D = $11.80

6.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Zoe has twice as many dimes as quarters. The coins have a total value of $8.10. Which equations represent this situation?

D = 2Q

Q = 2D

Q = D + 2

2D + Q = 810

10D + 25Q = 810

7.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

A collection of quarters and dimes is worth $6.75. the number of dimes is 4 less than 3 times the number of quarters. Which two equations represent this situation?

D = 3Q - 4

25Q + 10D = 675

Q = 3D - 4

D = 4 - 3Q

25Q + 10D = 6.75

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