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Area of triangle w/ explanation

Authored by Xu Chunshan

Mathematics

6th Grade

Area of triangle w/ explanation
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7 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find the area of the triangle ABC.

8 cm2

20 cm2

28 cm2

40 cm2

Answer explanation

Area of triangle ABC

= ½ b x h

= ½ CB x AB

= ½ (4 cm) x (10 cm)

= 20 cm²

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

What is the area of the triangle JLK?

10 m2

14 m2

70 m2

140 m2

Answer explanation

Area of triangle JLK

= ½ b x h

= ½ LK x JM

= ½ (14 m) x(10 m)

= 70 m²

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find the area of the triangle WXY.

20 cm2

27cm2

28 cm2

56 cm2

Answer explanation

Base YX of triangle WYX is 8 cm. Perpendicular height to base YX of triangle WYX is 7 cm.

Area of triangle WXY

= ½ b x h

= ½ (8 cm) x (7 cm)

= 28 cm²

4.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

Media Image

Given that the area of the triangle ABC is 48 cm², find the base BC of the triangle ABC that is perpendicular to its height AD of 6 cm.

Answer explanation

Area of triangle ABC = 48 cm²

½ base x its perpendicular height = 48 cm²

½ base BC  x AD    = 48 cm²

½ base BC  x 6 cm = 48 cm² 

½ base BC = 8 cm

base BC

= 2 x 8 cm

= 16 cm

5.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

Media Image

In the figure below, QRS is a straight line.

Find the area of triangle PQR.

Answer explanation

Area of triangle PQR

= ½ b x h

= ½ RQ x SP

= ½ (10 cm) x (14 cm)

= 70 cm²

6.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

Media Image

Look at the figure below.

Given that PS = 9 cm, SQ = 28 cm, PR = 14 cm and SR = 12 cm,

find the area of triangle PRQ.

Answer explanation

Ans: RQ = 28 – 12               

= 16 cm       

Area of triangle PRQ

= ½ b x h                         

= ½ RQ x PS                      

= ½ (16 cm) X (9cm)

= 72cm²   

7.

FILL IN THE BLANK QUESTION

5 mins • 1 pt

Media Image

QRSV is a rectangle.

Find the area of the shaded triangle QST.

Answer explanation

Area of triangle = ½ b x h

= ½ TS x QV

= ½ (2 cm) x(4 cm)

= 4 cm²

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