Ôn tập Nguyên hàm-Tích phân

 $\frac{1}{\cos^2x}+C$  

 $-\frac{1}{\cos^2x}+C$  

 $-\ln\left|\cos x\right|\ +C$  

 $\ln\left|\cos x\right|\ +C$  

 $3x^2-6x$  

 $3x^2-6x+C$  

 $\frac{x^4}{4}-x^3+5x+C$  

 $x^4-x^3+5x+C$  

3.ln(x) + C

$$\frac{\ln\left(x\right)}{3}+C$$  

$$\frac{\ln\left(x\right)}{3}$$  

$$\frac{\ln\left|2021x\right|}{3}+C$$  

8

12

36

4

$$3x^2-6x$$  

$$3x^2-6x+C$$  

$$\frac{x^4}{4}-x^3+5x+C$$  

$$x^4-x^3+5x+C$$  

 $L=\pi$  

 $L=-\pi$  

 $L=-2$  

 $L=0$  

 $F\left(x\right)=e^x+2$  

 $F\left(x\right)=e^x+3$  

 $F\left(x\right)=e^x+4$  

 $F\left(x\right)=e^x+1$  

$$\alpha x^{\left(\alpha-1\right)}+C$$  

$$\frac{x^{\left(\alpha+1\right)}}{\alpha+1}$$  +C

$$\left(\alpha+1\right)x^{\alpha}+C$$  

$$\frac{x^{\alpha}}{\ln\alpha}+C$$  

 $\frac{1}{2}\ln\left|2x+1\right|+C$  

 $2\ln\left|2x+1\right|+C$  

 $-\frac{1}{2\left(2x+1\right)^2}+C$  

 $\frac{1}{\left(2x+1\right)^2}+C$  

 $\sin x+C$  

 $-\cos x+C$  

 $-\sin x+C$  

 $\cot x+C$