chemistry

• a

• b

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Which of the following is incorrect ?

• Ethyl amine is soluble is water because it form H-bond with water and aniline has large hydrophobic part hence extent of H-bonding decreases .Hence solubility decreases

• Ethyl amine is stronger base than aniline because Ethyl has +I effect and lone pair of aniline is delocalised over the benze ring .

• Pkb value of Ethyl amine is greator than aniline

• None of the above

Although amino group is o,p− directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.

• Nitration is carried out in an medium. In an acidic medium, aniline is protonated to give anilinium ion (which is ortho and para -directing)

• Nitration gives only single product that is meta .

• Nitration is carried out in an acidic medium. In an acidic medium, aniline is protonated to give anilinium ion (which is meta-directing)

• none of the above

• a

• b

• c

• d

Aniline does not undergo Friedel-Crafts reaction.

• Friedel carft reaction reaquired lot of reaction condition

• A Friedel-Crafts reaction is carried out in the presence of AlCl3. But AlCl3 used as catalyst and is acidic in nature i.e ., Lewis acid whereas aniline is a strong Lewis base. Thus, aniline reacts with AlCl3 to form a salt.

• Friedel crafts reaction the lone pair of nitrogen is in reseonance with benzene ring hence can,t react .

• None of the above

Diazonium salts of aromatic amines are more stable than those of aliphatic amines

• Aliphatic diazonium are resonance stablise where as aromatic diazonium is not

• Aromatic benzene diazonium are resonance stablise wheres as aliphatic diazonium does not

• Resonace is not possible in both case

• None of the above

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• d

• a

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• c

• d

• a

• b

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• d

Arrange the In increasing order of boiling point: C₂H₅OH, (CH₃)₂NH, C₂H₅NH²R

• (CH3)2 NH < C2H5NH2 < C2H5OH

• (CH3)2 NH < C2H5OH C2H5NH2 <

• C2H5OH<(CH3)2 NH < C2H5NH2 

• None of the above