BUG@MASTER

Point out the error, if any in the program.

#include<stdio.h>

int main()

{

    int a = 10;

    switch(a)

    {

    }

    printf("This is c program.");

                    return 0;

}

• Error: No case statement specified

• Error: No default specified

• Error: infinite loop occurs

• No Error

Point out the error, if any in the program.

#include<stdio.h>

int main()

{

    int i = 1;

    switch(i)

    {

        printf("This is c program.");

        case 1:

            printf("Case1");

            break;

        case 2:

            printf("Case2");

            break;

    }

return 0;

}

• Error: No default specified

• Error: Invalid printf statement after switch statement

• None of above

• No Error and prints "Case1"

Point out the error, if any in the while loop.

#include<stdio.h>

int main()

{

    int i=1;

    while()

    {

        printf("%d\n", i++);

        if(i>10)

           break;

    }

    return 0;

}

• There should be at least a semicolon in the while

• The while loop should be replaced with for loop

• There should be a condition in the while loop

• No error

Point out the error, if any in the program.

#include<stdio.h>

int main()

{

    int i = 1;

    switch(i)

    {

        case 1:

           printf("Case1");

           break;

        case 1*2+4:

           printf("Case2");

           break;

    }

return 0;

}

• Error: in switch statement

• Error: in case 1*2+4 statement

• No Error

• Error: No default specified

Point out the error, if any in the while loop.

#include<stdio.h>

int main()

{

    int i=1;

    while()

    {

        printf("%d\n", i++);

        if(i>10)

           break;

    }

    return 0;

}

• There should be at least a semicolon in the while

• The while loop should be replaced with for loop

• No error

• There should be a condition in the while loop

What will be the output of the following C code?

#include <stdio.h>

int main()

{

int y = 10000;

int y = 34;

printf("Hello World! %d\n", y);

return 0;

}

• Hello World! 34

• Compile time error

• Hello World! 1000

• Hello World! followed by a junk value

What will be the final values of i and j in the following C code?

#include <stdio.h>

int x = 0;

int f()

{

if (x == 0)

return x + 1;

else

return x - 1;

}

int g()

{

return x++;

}

int main()

{

int i = (f() + g()) | g(); //bitwise or

int j = g() | (f() + g()); //bitwise or

}

• i value is 1 and j value is 1

• i value is 0 and j value is 0

• i value is 1 and j value is undefined

• i and j value are undefined

What is the problem in the following C declarations?

int func(int);

double func(int);

int func(float);

• A function with same name cannot have different signatures

• A function with same name cannot have different return types

• A function with same name cannot have different number of parameters

• All of the mentioned

Which of the following errors would be reported by the compiler on compiling the program given below?

#include<stdio.h>

int main()

{

    int a = 5;

    switch(a)

    {

        case 1:

        printf("First");

        case 2:

        printf("Second");

        case 3 + 2:

        printf("Third");

        case 5:

        printf("Final");

        break;

    }

    return 0;

}

• There is no break statement in each case.

• Expression as in case 3 + 2 is not allowed

• No error will be reported.

• Duplicate case case 5:

Point out the error in the program

f(int a, int b)

{

    int a;

    a = 20;

    return a;

}

• Missing parenthesis in return statement

• The function should be defined as int f(int a, int b

• Redeclaration of a

• None of above