Determine el dominio y rango de la siguiente función f ( x ) = − ∣ x + 5 ∣ f\left(x\right)=-\left|x+5\right| f ( x ) = − ∣ x + 5 ∣

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R [ R a n ( f ) = < − ∞ ; 0 ] \left[Ran\left(f\right)=<-\infty\ ;\ 0\ \right] [ R a n ( f ) = < − ∞ ; 0 ]

D o m ( f ) = R Dom\left(f\right)=\ R D o m ( f ) = R R a n ( f ) = [ 0 ; + ∞ > ] Ran\left(f\right)=\left[0\ ;\ +\infty>\right] R a n ( f ) = [ 0 ; + ∞ > ]

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R R a n ( f ) = [ 5 ; + ∞ > ] Ran\left(f\right)=\left[5\ ;\ +\infty>\right] R a n ( f ) = [ 5 ; + ∞ > ]

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R R a n ( f ) = R Ran\left(f\right)=R R a n ( f ) = R

La solución de la desigualdad ∣ x ∣ < − 2 \left|x\right|<-2 ∣ x ∣ < − 2 es:

x < − 2 y x > 2 x<-2\ y\ x>2 x < − 2 y x > 2

( − ∞ , − 2 ] \left(-\infty,-2\right] ( − ∞ , − 2 ]

Determine el dominio y rango de la siguiente función f ( x ) = 2 x − 8 f\left(x\right)=\sqrt{2x-8} f ( x ) = 2 x − 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

D o m ( f ) = [ 4 ; + ∞ > ] Dom\left(f\right)=\left[4\ ;\ +\infty>\right] D o m ( f ) = [ 4 ; + ∞ > ] R a n ( f ) = [ 0 ; + ∞ > ] Ran\left(f\right)=\left[0\ ;\ +\infty>\right] R a n ( f ) = [ 0 ; + ∞ > ]

D o m ( f ) = [ 8 ; + ∞ > ] Dom\left(f\right)=\left[8\ ;\ +\infty>\right] D o m ( f ) = [ 8 ; + ∞ > ] R a n ( f ) = [ 0 ; + ∞ > ] Ran\left(f\right)=\left[0\ ;\ +\infty>\right] R a n ( f ) = [ 0 ; + ∞ > ]

[ D o m ( f ) = < − ∞ ; 4 ] \left[Dom\left(f\right)=<-\infty\ ;\ 4\ \right] [ D o m ( f ) = < − ∞ ; 4 ] R a n ( f ) = [ 4 ; + ∞ > ] Ran\left(f\right)=\left[4\ ;\ +\infty>\right] R a n ( f ) = [ 4 ; + ∞ > ]

D o m ( f ) = [ − 4 ; + ∞ > ] Dom\left(f\right)=\left[-4\ ;\ +\infty>\ \right] D o m ( f ) = [ − 4 ; + ∞ > ] [ R a n ( f ) = < − ∞ ; 0 ] \left[Ran\left(f\right)=<-\infty\ ;\ 0\ \right] [ R a n ( f ) = < − ∞ ; 0 ]

Determine el dominio y rango de la siguiente función f ( x ) = x + 5 − 3 f\left(x\right)=\sqrt{x+5}-3 f ( x ) = x + 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 3

D o m ( f ) = [ − 5 ; + ∞ > ] Dom\left(f\right)=\left[-5\ ;\ +\infty>\right] D o m ( f ) = [ − 5 ; + ∞ > ] R a n ( f ) = [ − 3 ; + ∞ > ] Ran\left(f\right)=\left[-3\ ;\ +\infty>\right] R a n ( f ) = [ − 3 ; + ∞ > ]

D o m ( f ) = [ 5 ; + ∞ > ] Dom\left(f\right)=\left[5\ ;\ +\infty>\right] D o m ( f ) = [ 5 ; + ∞ > ] R a n ( f ) = [ 3 ; + ∞ > ] Ran\left(f\right)=\left[3\ ;\ +\infty>\right] R a n ( f ) = [ 3 ; + ∞ > ]

D o m ( f ) = [ − 3 ; + ∞ > ] Dom\left(f\right)=\left[-3\ ;\ +\infty>\right] D o m ( f ) = [ − 3 ; + ∞ > ] R a n ( f ) = [ − 5 ; + ∞ > ] Ran\left(f\right)=\left[-5\ ;\ +\infty>\right] R a n ( f ) = [ − 5 ; + ∞ > ]

D o m ( f ) = < − 5 ; + ∞ > Dom\left(f\right)=<-5\ ;\ +\infty> D o m ( f ) = < − 5 ; + ∞ > R a n ( f ) = < − 3 ; + ∞ > Ran\left(f\right)=<-3\ ;\ +\infty> R a n ( f ) = < − 3 ; + ∞ >

La solución de la desigualdad ∣ x − 1 ∣ > − 1 \left|x-1\right|>-1 ∣ x − 1 ∣ > − 1 es:

( − ∞ , ∞ ) \left(-\infty,\ \infty\right) ( − ∞ , ∞ )

( 0 , ∞ ) \left(0,\ \infty\right) ( 0 , ∞ )

( − ∞ , − 1 ) ∪ ( 1 , ∞ ) \left(-\infty,-1\right)\cup\left(1,\infty\right) ( − ∞ , − 1 ) ∪ ( 1 , ∞ )

Hallar el conjunto solución de: ∣ 3 x − 16 ∣ = 5 x \left|3x-16\right|=5x ∣ 3 x − 1 6 ∣ = 5 x

C S = { 2 } CS=\left\{2\right\} C S = { 2 }

C S = { 8 } CS=\left\{8\right\} C S = { 8 }

C S = { − 2 } CS=\left\{-2\right\} C S = { − 2 }

C S = { − 8 } CS=\left\{-8\right\} C S = { − 8 }

C S = { 2 ; − 8 } CS=\left\{2;-8\right\} C S = { 2 ; − 8 }

La solución de esta ecuación ∣ x + 2 ∣ = − 7 \left|x+2\right|=-7 ∣ x + 2 ∣ = − 7 es...

x 1 = − 4 x 2 = 11 x_1=-4\ \ \ \ x_2=11 x 1 = − 4 x 2 = 1 1

Determine el dominio y rango de la siguiente función f ( x ) = ∣ 2 x − 8 ∣ + 4 f\left(x\right)=\left|2x-8\right|+4 f ( x ) = ∣ 2 x − 8 ∣ + 4

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R R a n ( f ) = [ 4 ; + ∞ > ] Ran\left(f\right)=\left[4\ ;\ +\infty>\right] R a n ( f ) = [ 4 ; + ∞ > ]

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R R a n ( f ) = [ − 4 ; + ∞ > ] Ran\left(f\right)=\left[-4\ ;+\infty>\right] R a n ( f ) = [ − 4 ; + ∞ > ]

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R [ R a n ( f ) = < − ∞ ; 4 ] \left[Ran\left(f\right)=<-\infty\ ;\ 4\ \right] [ R a n ( f ) = < − ∞ ; 4 ]

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R R a n ( f ) = [ 0 ; + ∞ > ] Ran\left(f\right)=\left[0\ ;\ +\infty>\right] R a n ( f ) = [ 0 ; + ∞ > ]

¿Cómo se define el valor absoluto de un número?

La distancia del número a cero

El inverso multiplicativo del número

La solución de la desigualdad ∣ x − 2 ∣ > 3 \left|x-2\right|>3 ∣ x − 2 ∣ > 3 corresponde con la solución de:

x − 2 > 3 ∪ x − 2 < − 3 x-2>3\ \ \ \cup\ \ \ x-2<-3 x − 2 > 3 ∪ x − 2 < − 3

x − 2 > 3 ∩ x − 2 < − 3 x-2>3\ \ \ \cap\ \ x-2<-3 x − 2 > 3 ∩ x − 2 < − 3

− 3 < x − 2 < 3 -3<x-2<3 − 3 < x − 2 < 3

x − 2 = − 3 y x − 2 = − 3 x-2=-3\ \ \ y\ \ \ x-2=-3 x − 2 = − 3 y x − 2 = − 3

∣ x ∣ < − 3 \left|x\right|<-3 ∣ x ∣ < − 3

no tiene solucion para los números reales

¿Qué alternativa es FALSA?

∣ − 3 ∣ < − 2 \left|-3\right|<-2 ∣ − 3 ∣ < − 2

∣ 4 ∣ < ∣ − 5 ∣ \left|4\right|<\left|-5\right| ∣ 4 ∣ < ∣ − 5 ∣

0 < ∣ − 10 ∣ 0<\left|-10\right| 0 < ∣ − 1 0 ∣

Si x = 0 x=0 x = 0 , entonces ∣ x ∣ = 0 \left|x\right|=0 ∣ x ∣ = 0

∣ − 7 ∣ ≤ 7 \left|-7\right|\le7 ∣ − 7 ∣ ≤ 7

∣ x ∣ < 4 \left|x\right|<4 ∣ x ∣ < 4

− 4 < x < 4 -4<x<4 − 4 < x < 4

4 < x < − 4 4<x<-4 4 < x < − 4

¿Cómo se define el valor absoluto?

La distancia de un número a cero

El inverso multiplicativo de un número

∣ x + 5 ∣ ≥ 3 \left|x+5\right|\ge3 ∣ x + 5 ∣ ≥ 3

( − ∞ , − 8 ] ∪ [ − 2 , + ∞ ) \left(-\infty,-8\right]\cup\left[-2,+\infty\right) ( − ∞ , − 8 ] ∪ [ − 2 , + ∞ )

( − ∞ , − 8 ] ∩ [ − 2 , + ∞ ) \left(-\infty,-8\right]\cap\left[-2,+\infty\right) ( − ∞ , − 8 ] ∩ [ − 2 , + ∞ )

( − 5 , − 3 ) ∩ ( 5 , 3 ) \left(-5,-3\right)\cap\left(5,3\right) ( − 5 , − 3 ) ∩ ( 5 , 3 )

\left[-8,-2\right)\cup\left[2,8\right] [ − 8 , − 2 ) ∪ [ 2 , 8 ]

∣ 2 x − 4 ∣ − 3 ≥ x + 5 \left|2x-4\right|-3\ge x+5 ∣ 2 x − 4 ∣ − 3 ≥ x + 5

( − ∞ ; − 4 3 ] ∪ [ 12 ; ∞ ) \left(-\infty;-\frac{4}{3}\right]\cup\left[12;\infty\right) ( − ∞ ; − 3 4 ] ∪ [ 1 2 ; ∞ )

− 4 3 ≤ x ≤ 12 -\frac{4}{3}\le x\le12 − 3 4 ≤ x ≤ 1 2

( − 12 ; − 4 / 3 ) \left(-12;-4/3\right) ( − 1 2 ; − 4 / 3 )

¿Cómo se define el valor absoluto?

La distancia de un número a cero

El inverso multiplicativo de un número

∣ x − 3 ∣ ≤ 12 \left|x-3\right|\le12 ∣ x − 3 ∣ ≤ 1 2

[ − 9 , 15 ] \left[-9,15\right] [ − 9 , 1 5 ]

( − 3 , 12 ) \left(-3,12\right) ( − 3 , 1 2 )

( − 9 , 15 ) \left(-9,15\right) ( − 9 , 1 5 )

[ 9 , 15 ] \left[9,15\right] [ 9 , 1 5 ]

Determine el dominio y rango de la siguiente función f ( x ) = − ∣ x + 5 ∣ f\left(x\right)=-\left|x+5\right| f ( x ) = − ∣ x + 5 ∣

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R [ R a n ( f ) = < − ∞ ; 0 ] \left[Ran\left(f\right)=<-\infty\ ;\ 0\ \right] [ R a n ( f ) = < − ∞ ; 0 ]

D o m ( f ) = R Dom\left(f\right)=\ R D o m ( f ) = R R a n ( f ) = [ 0 ; + ∞ > ] Ran\left(f\right)=\left[0\ ;\ +\infty>\right] R a n ( f ) = [ 0 ; + ∞ > ]

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R R a n ( f ) = [ 5 ; + ∞ > ] Ran\left(f\right)=\left[5\ ;\ +\infty>\right] R a n ( f ) = [ 5 ; + ∞ > ]

D o m ( f ) = R Dom\left(f\right)=R D o m ( f ) = R R a n ( f ) = R Ran\left(f\right)=R R a n ( f ) = R

La solución de la desigualdad ∣ x ∣ < − 2 \left|x\right|<-2 ∣ x ∣ < − 2 es:

x < − 2 y x > 2 x<-2\ y\ x>2 x < − 2 y x > 2

( − ∞ , − 2 ] \left(-\infty,-2\right] ( − ∞ , − 2 ]

Determine el dominio y rango de la siguiente función f ( x ) = 2 x − 8 f\left(x\right)=\sqrt{2x-8} f ( x ) = 2 x − 8 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

D o m ( f ) = [ 4 ; + ∞ > ] Dom\left(f\right)=\left[4\ ;\ +\infty>\right] D o m ( f ) = [ 4 ; + ∞ > ] R a n ( f ) = [ 0 ; + ∞ > ] Ran\left(f\right)=\left[0\ ;\ +\infty>\right] R a n ( f ) = [ 0 ; + ∞ > ]

D o m ( f ) = [ 8 ; + ∞ > ] Dom\left(f\right)=\left[8\ ;\ +\infty>\right] D o m ( f ) = [ 8 ; + ∞ > ] R a n ( f ) = [ 0 ; + ∞ > ] Ran\left(f\right)=\left[0\ ;\ +\infty>\right] R a n ( f ) = [ 0 ; + ∞ > ]

[ D o m ( f ) = < − ∞ ; 4 ] \left[Dom\left(f\right)=<-\infty\ ;\ 4\ \right] [ D o m ( f ) = < − ∞ ; 4 ] R a n ( f ) = [ 4 ; + ∞ > ] Ran\left(f\right)=\left[4\ ;\ +\infty>\right] R a n ( f ) = [ 4 ; + ∞ > ]

D o m ( f ) = [ − 4 ; + ∞ > ] Dom\left(f\right)=\left[-4\ ;\ +\infty>\ \right] D o m ( f ) = [ − 4 ; + ∞ > ] [ R a n ( f ) = < − ∞ ; 0 ] \left[Ran\left(f\right)=<-\infty\ ;\ 0\ \right] [ R a n ( f ) = < − ∞ ; 0 ]

2023-2 Osk_valor absoluto 102

Authored by Os.kr Profesor

Mathematics

University

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MULTIPLE SELECT QUESTION

30 sec • 1 pt

Hallar los elementos del conjunto solución de:
$\left|2x-1\right|=5$

-2

-3

No tiene solución

MULTIPLE SELECT QUESTION

30 sec • 1 pt

La(s) solución(es) de la ecuación:
$\left|2-x\right|=5$ es (son)...
(Marque todas las posibles)

$x=-3$

$x=7$

$x=3$

$x=0$

MULTIPLE CHOICE QUESTION

30 sec • 2 pts

Encontrar el valor de "x" en: |3x-2|=|2x+3|

C.S={-1/3 ; 3}

C.S={1/5 ; 3}

C.S={-1/5 ; 5}

No tiene solución

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Determine el dominio y rango de la siguiente función

$f\left(x\right)=-\left|x+5\right|$

$Dom\left(f\right)=\ R$ $Ran\left(f\right)=\left[0\ ;\ +\infty>\right]$

$Dom\left(f\right)=R$ $Ran\left(f\right)=\left[5\ ;\ +\infty>\right]$

$Dom\left(f\right)=R$ $\left[Ran\left(f\right)=<-\infty\ ;\ 0\ \right]$

$Dom\left(f\right)=R$ $Ran\left(f\right)=R$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

La solución de la desigualdad $\left|x\right|<-2$ es:

No hay solución

$x<-2\ y\ x>2$

Todos los reales

$\left(-\infty,-2\right]$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Determine el dominio y rango de la siguiente función

$f\left(x\right)=\sqrt{2x-8}$

$Dom\left(f\right)=\left[4\ ;\ +\infty>\right]$ $Ran\left(f\right)=\left[0\ ;\ +\infty>\right]$

$Dom\left(f\right)=\left[8\ ;\ +\infty>\right]$ $Ran\left(f\right)=\left[0\ ;\ +\infty>\right]$

$\left[Dom\left(f\right)=<-\infty\ ;\ 4\ \right]$ $Ran\left(f\right)=\left[4\ ;\ +\infty>\right]$

$Dom\left(f\right)=\left[-4\ ;\ +\infty>\ \right]$ $\left[Ran\left(f\right)=<-\infty\ ;\ 0\ \right]$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\left|2x-3\right|\le1$ Determina el intervalo que justifica la solución de la inecuación

[1,2]

[-1,2]

[-2,1]

[-2 ,-1]

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2023-2 Osk_valor absoluto 102

Hallar los elementos del conjunto solución de: ∣2x−1∣=5\left|2x-1\right|=5∣2x−1∣=5

La(s) solución(es) de la ecuación: \left|2-x\right|=5∣2−x∣=5 es (son)...(Marque todas las posibles)

Encontrar el valor de "x" en: |3x-2|=|2x+3|

Determine el dominio y rango de la siguiente función f(x)=−∣x+5∣f\left(x\right)=-\left|x+5\right|f(x)=−∣x+5∣

La solución de la desigualdad ∣x∣<−2\left|x\right|<-2∣x∣<−2 es:

Determine el dominio y rango de la siguiente función f(x)=2x−8f\left(x\right)=\sqrt{2x-8}f(x)=2x−8​

∣2x−3∣≤1\left|2x-3\right|\le1∣2x−3∣≤1 Determina el intervalo que justifica la solución de la inecuación

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Hallar los elementos del conjunto solución de:
$\left|2x-1\right|=5$

La(s) solución(es) de la ecuación:
$\left|2-x\right|=5$ es (son)...
(Marque todas las posibles)

Determine el dominio y rango de la siguiente función

$f\left(x\right)=-\left|x+5\right|$

La solución de la desigualdad $\left|x\right|<-2$ es:

Determine el dominio y rango de la siguiente función

$f\left(x\right)=\sqrt{2x-8}$

$\left|2x-3\right|\le1$ Determina el intervalo que justifica la solución de la inecuación