Arah dari vektor A B → \overrightarrow{AB} A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> adalah...

( − 4 , 2 ) \left(-4,2\right) ( − 4 , 2 )

( 4 , − 2 ) \left(4,-2\right) ( 4 , − 2 )

( 4 , 2 ) \left(4,2\right) ( 4 , 2 )

( − 4 , − 2 ) \left(-4,-2\right) ( − 4 , − 2 )

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b ⃗ = − i + 3 j + 7 k d a n b⃗=-i+3j+7k\ dan\ b ⃗ = − i + 3 j + 7 k d a n c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ − b ⃗ + c ⃗ ! c⃗=5i-2j-k\ Tentukan\ a⃗-b⃗+c⃗! c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ − b ⃗ + c ⃗ !

( 8 , 0 , − 4 ) \left(8,0,-4\right) ( 8 , 0 , − 4 )

( − 8 , 0 , − 4 ) \left(-8,0,-4\right) ( − 8 , 0 , − 4 )

( 6 , 0 , − 4 ) \left(6,0,-4\right) ( 6 , 0 , − 4 )

( − 6 , 0 , − 4 ) \left(-6,0,-4\right) ( − 6 , 0 , − 4 )

( 6 , 0 , 4 ) \left(6,0,4\right) ( 6 , 0 , 4 )

Jika p → = 5 i − 4 j + 3 k \overrightarrow{p}=5i-4j+3k p <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 5 i − 4 j + 3 k , q → = 2 i + 7 k \overrightarrow{q}=2i+7k q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 2 i + 7 k , r → = 6 j − 2 k \overrightarrow{r}=6j-2k r <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 6 j − 2 k Nilai dari p → . ( q → + r → ) \overrightarrow{p}\ .\ \left(\overrightarrow{q}\ +\overrightarrow{r}\right) p <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> . ( q <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + r <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> )

D. − 38 i − 19 j + 38 k -38i-19j+38k − 3 8 i − 1 9 j + 3 8 k

A. − 38 i − 19 j − 38 k -38i-19j-38k − 3 8 i − 1 9 j − 3 8 k

B. 19 i − 39 j + 38 k 19i-39j+38k 1 9 i − 3 9 j + 3 8 k

D. 38 i + 19 j + 38 k 38i+19j+38k 3 8 i + 1 9 j + 3 8 k

E. 38 i − 39 j + 19 k 38i-39j+19k 3 8 i − 3 9 j + 1 9 k

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b → = − 𝑖 + 3 𝑗 + 7 𝑘 d a n c → = 5 𝑖 − 2 𝑗 − 𝑘 \overrightarrow{b}=−𝑖+3𝑗+7𝑘\ dan\ \ \overrightarrow{c}=5𝑖−2𝑗−𝑘 b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − i + 3 j + 7 k d a n c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 5 i − 2 j − k T e n t u k a n a ⃗ − c ⃗ ! Tentukan\ a⃗-c⃗! T e n t u k a n a ⃗ − c ⃗ !

( − 3 , 7 , 5 ) (-3,7,5) ( − 3 , 7 , 5 )

( − 3 , 7 , − 5 ) (-3,7,-5) ( − 3 , 7 , − 5 )

( 3 , 7 , 5 ) (3,7,5) ( 3 , 7 , 5 )

( 7 , 7 , 3 ) \left(7,7,3\right) ( 7 , 7 , 3 )

( − 7 , 7 , 3 ) \left(-7,7,3\right) ( − 7 , 7 , 3 )

Tentukan Vektor-Vektor pada Gambar 2 dalam ungkapan Vektor satuan

∣P∣=3i+3j dan ∣Q∣=-5i-3j

∣P∣=3i-3j dan ∣Q∣=-5i+3j

∣P∣=3i+3j dan ∣Q∣=-5i-3j

∣P∣=-3i+3j dan ∣Q∣=5i+3j

∣P∣=-3i-3j dan ∣Q∣=-5i-3j

Jika u ‾ = ( 3 , − 5 ) \overline{u}=\left(3,-5\right) u = ( 3 , − 5 ) dan v ‾ = ( − 4 , − 1 ) \overline{v}=\left(-4,-1\right) v = ( − 4 , − 1 ) . Nilai 2 u ‾ − v ‾ = ⋅ ⋅ ⋅ 2\overline{u}-\overline{v}=\cdot\cdot\cdot 2 u − v = ⋅ ⋅ ⋅

( 10 , − 9 ) \left(10,-9\right) ( 1 0 , − 9 )

( − 1 , − 6 ) \left(-1,-6\right) ( − 1 , − 6 )

( 7 , − 4 ) \left(7,-4\right) ( 7 , − 4 )

( 2 , − 11 ) \left(2,-11\right) ( 2 , − 1 1 )

( 11 , − 3 ) \left(11,-3\right) ( 1 1 , − 3 )

D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k Diketahui\ a⃗=2i+5j+4k D i k e t a h u i a ⃗ = 2 i + 5 j + 4 k b ⃗ = − i + 3 j + 7 k d a n b⃗=-i+3j+7k\ dan b ⃗ = − i + 3 j + 7 k d a n c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ + b ⃗ ! c⃗=5i-2j-k\ Tentukan\ a⃗+b⃗! c ⃗ = 5 i − 2 j − k T e n t u k a n a ⃗ + b ⃗ !

i ‾ + 8 j ‾ + 11 k ‾ \overline{i}+8\overline{j}+11\overline{k} i + 8 j + 1 1 k

3 i ‾ + 8 j ‾ + 11 k ‾ 3\overline{i}+8\overline{j}+11\overline{k} 3 i + 8 j + 1 1 k

3 i ‾ − 8 j ‾ + 11 k ‾ 3\overline{i}-8\overline{j}+11\overline{k} 3 i − 8 j + 1 1 k

i ‾ − 8 j ‾ + 11 k ‾ \overline{i}-8\overline{j}+11\overline{k} i − 8 j + 1 1 k

− i ‾ + 8 j ‾ + 11 k ‾ -\overline{i}+8\overline{j}+11\overline{k} − i + 8 j + 1 1 k

vektor

Authored by tukang belajar

Mathematics

10th Grade

CCSS covered

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FILL IN THE BLANK QUESTION

30 sec • 1 pt

Diketahui vektor-vektor $\overrightarrow{a\ }=-2i-1j+8k$ dan $\overrightarrow{b\ }=-22i+9j-2k$ , panjang vektor $\overrightarrow{b}+\overrightarrow{a}$ adalah ... .

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Besar resultan dari vektor $\overrightarrow{p\ }=\ \left(_{\ 23}^{\ \ 8}\right)$ dan $\overrightarrow{q\ }=\left(_{-2}^{12}\right)$ adalah ... .

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Jika besar sudut antara vektor $\overrightarrow{p}=-2\overrightarrow{i}-1\overrightarrow{j}+3\overrightarrow{k}$ dan $\overrightarrow{q}=1\overrightarrow{i}-3\overrightarrow{j}+2\overrightarrow{k}$ adalah $\alpha$ , maka besar $\alpha$ adalah ... $\degree$ . (Jawab hanya dengan angka saja)

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Diketahui vektor-vektor $\overrightarrow{a\ }=-2\overrightarrow{i\ }-1\overrightarrow{j}+8\overrightarrow{k}$ dan $\overrightarrow{b\ }=-22\overrightarrow{i}+9j-2\overrightarrow{k}$ , panjang vektor $\overrightarrow{b}+\overrightarrow{a}$ adalah ... .

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

(-1,12)

(-7,-2)

(-7,2)

(7,2)

(1,-12)

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Diketahui\ ā=(2,0,-2)\ \ dan\$ $ū=(1,-1,1).$
$Tentukan\ \ \ ā-ū!$

$(1,-1,-3)$

$(1,-1,3)$

$(-1,-1,3)$

$(-1,1,-3)$

$(-1,-1,-3)$

$Tentukan\ vektor\ basis\ (OA)⃗!$

$(2,5,3)$

$(2,-5,3)$

$(2,-5,-3)$

$(-2,-5,3)$

$(-2,-5,-3)$

Arah dari vektor $\overrightarrow{AB}$ adalah...

$\left(4,-2\right)$

$\left(4,2\right)$

$\left(-4,-2\right)$

$\left(-4,2\right)$

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vektor

Diketahui vektor-vektor a →=−2i−1j+8k\overrightarrow{a\ }=-2i-1j+8ka =−2i−1j+8k dan b →=−22i+9j−2k\overrightarrow{b\ }=-22i+9j-2kb =−22i+9j−2k , panjang vektor b→+a→\overrightarrow{b}+\overrightarrow{a}b+a adalah ... .

Besar resultan dari vektor p →= ( 23 8)\overrightarrow{p\ }=\ \left(_{\ 23}^{\ \ 8}\right)p ​= ( 23 8​) dan q →=(−212)\overrightarrow{q\ }=\left(_{-2}^{12}\right)q ​=(−212​) adalah ... .

Diketahui aˉ=(2,0,−2) dan Diketahui\ ā=(2,0,-2)\ \ dan\ Diketahui aˉ=(2,0,−2) dan uˉ=(1,−1,1).ū=(1,-1,1).uˉ=(1,−1,1). Tentukan aˉ−uˉ!Tentukan\ \ \ ā-ū!Tentukan aˉ−uˉ!

Tentukan vektor basis (OA)⃗!Tentukan\ vektor\ basis\ (OA)⃗!Tentukan vektor basis (OA)⃗!

Arah dari vektor AB→\overrightarrow{AB}AB adalah...

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Diketahui vektor-vektor $\overrightarrow{a\ }=-2i-1j+8k$ dan $\overrightarrow{b\ }=-22i+9j-2k$ , panjang vektor $\overrightarrow{b}+\overrightarrow{a}$ adalah ... .

Besar resultan dari vektor $\overrightarrow{p\ }=\ \left(_{\ 23}^{\ \ 8}\right)$ dan $\overrightarrow{q\ }=\left(_{-2}^{12}\right)$ adalah ... .

$Diketahui\ ā=(2,0,-2)\ \ dan\$ $ū=(1,-1,1).$
$Tentukan\ \ \ ā-ū!$

$Tentukan\ vektor\ basis\ (OA)⃗!$

Arah dari vektor $\overrightarrow{AB}$ adalah...