
Bases de datos SQL
Quiz
•
Computers
•
Professional Development
•
Practice Problem
•
Hard
Mónica Vives
Used 3+ times
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11 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Si solo queremos mostrar 3 elementos en una SQL, ¿qué comando utilizaremos?
Count 3
Like 3
Show 3
Limit 3
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Queremos mostrar clientes que su nombre empiece por "C"
Name = ‘C%’
Name like ‘C%’
Name like = ‘C%’
a y b con correctas
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Queremos mostrar el número de ejemplares vendidos de cada cuadro de la tabla ventas que vemos a la izda
select SUM(EjemplaresVendidos) from cuadros
select COUNT(EjemplaresVendidos) from cuadros
select NUMBER(EjemplaresVendidos) from cuadros
A Y B SON CORRECTAS
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Tenemos el campo Precio en la tabla Cuadros ¿Cómo conseguimos el precio con el 16% de IVA?
SELECT Precio + Precio * 0.16 FROM Cuadros
SELECT Precio + Precio + 0.16% FROM Cuadros
SELECT Precio * 0.16 FROM Cuadros
a y b son correctas
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Muestra el apellido de los clientes cuya primera letra del apellido empieza por O, P, Q, R, S, T, U o V
SELECT Apellidos FROM clientes WHERE Apellido like 'O%' OR 'P%' OR 'Q%' OR 'R%' OR 'S%' OR 'T%' OR 'U%' OR 'V%'
SELECT Apellidos FROM clientes WHERE Apellidos regexp’^[O,P,Q,R,S,T,U,V]’;
Las dos son correctas
Ninguna es correcta
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Muestra el nombre de los cuadros cuyo precio es más alto que la media de los precios de los cuadros.
SELECT nombre FROM cuadros WHERE precio IN > (SELECT AVG(precio) FROM cuadros
SELECT nombre FROM cuadros WHERE precio > (SELECT AVG(precio) FROM cuadros
Las dos son correctas
Ninguna es correcta
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Muestra las especialidades que tienen más de 4 empleados
SELECT count(nombre), especialidad FROM empleado GROUP BY especialidad WHERE count(nombre) > 4
SELECT count(nombre), especialidad FROM empleado HAVING count(nombre) > 4
SELECT count(nombre), especialidad FROM empleado GROUP BY especialidad HAVING count(nombre) > 4
a y c son correctas
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