Stoichiometry

Quiz

•

Chemistry

•

10th Grade

•

Practice Problem

•

Medium

•

112.43.c.9.C

Standards-aligned

Juan Hernandez

Used 132+ times

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15 questions

Show all answers

1.

DRAG AND DROP QUESTION

1 min • 1 pt

1 N₂ + 3 H₂ → 2NH₃
How many moles of hydrogen, H₂, are needed to react with 2.00 mol of nitrogen, N₂?
(a) mol N₂ ÷ (b) mol N₂ x (c) mol H₂ = (d) mol H₂

2.00

1

3

6

Tags

112.43.c.9.C

2.

MATH RESPONSE QUESTION

1 min • 1 pt

2H₂ + O₂ → 2H₂O
How many moles of water, H₂O, can be produced if 8.00 moles of H₂ are used? (Show your work and answer)

Mathematical Equivalence

ON

Tags

112.43.c.9.C

3.

DROPDOWN QUESTION

1 min • 1 pt

3 Mg + 1 Fe₂O₃ → 3 MgO + 2 Fe
Identify the mole ratios for the following pairs:
(a) Mg : (b) Fe
(c) Fe₂O₃ : (d) Fe
1 Fe₂O₃ : (e) MgO

3

2

1

Tags

112.43.c.9.C

4.

DRAG AND DROP QUESTION

1 min • 1 pt

1 Cl₂ + 2 KBr → 1 Br₂ + 2 KCl
How many grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide (KBr)?
(a) + 35 = 74g x 2 = 148g 39 + 80 = (b) g x 2 = 238g
(c) / (d) x 148 = (e) g

39

119

356

238

221

Tags

112.43.c.9.C

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
How many moles of carbon dioxide (CO₂) are produced from the combustion of 110.0 g of CH₄ (molar mass = 16 g)?

13.7 mol

2.75 mol

6.85 mol

6.11 mol

Tags

112.43.c.9.C

6.

DROPDOWN QUESTION

1 min • 1 pt

1 B₂H₅ + 3 O₂ → 2 HBO₂ + 2 H₂O
What mass of O₂ will be needed to burn 36.1 g of B₂H₅?
16 x 2 = (a) x 3 = 96 g (11 x 2) + (1 x 5) = 27 g
(b) / (c) x (d) = (e) g

32

36.1

27

96

128.356

Tags

112.43.c.9.C

7.

DRAG AND DROP QUESTION

1 min • 1 pt

Balance the following reaction:
(a) CaC₂ + (b) H₂O → (c) C₂H₂ + (d) Ca(OH)₂

1

2

Tags

112.43.c.9.C

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Stoichiometry

15 questions

1 N₂ + 3 H₂ → 2NH₃
How many moles of hydrogen, H₂, are needed to react with 2.00 mol of nitrogen, N₂?
(a) mol N₂ ÷ (b) mol N₂ x (c) mol H₂ = (d) mol H₂

2H₂ + O₂ → 2H₂O
How many moles of water, H₂O, can be produced if 8.00 moles of H₂ are used? (Show your work and answer)

3 Mg + 1 Fe₂O₃ → 3 MgO + 2 Fe
Identify the mole ratios for the following pairs:
(a) Mg : (b) Fe
(c) Fe₂O₃ : (d) Fe
1 Fe₂O₃ : (e) MgO

1 Cl₂ + 2 KBr → 1 Br₂ + 2 KCl
How many grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide (KBr)?
(a) + 35 = 74g x 2 = 148g 39 + 80 = (b) g x 2 = 238g
(c) / (d) x 148 = (e) g

1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
How many moles of carbon dioxide (CO₂) are produced from the combustion of 110.0 g of CH₄ (molar mass = 16 g)?

1 B₂H₅ + 3 O₂ → 2 HBO₂ + 2 H₂O
What mass of O₂ will be needed to burn 36.1 g of B₂H₅?
16 x 2 = (a) x 3 = 96 g (11 x 2) + (1 x 5) = 27 g
(b) / (c) x (d) = (e) g

Balance the following reaction:
(a) CaC₂ + (b) H₂O → (c) C₂H₂ + (d) Ca(OH)₂

1 Fe₂O₃ + 3H₂ → 2 Fe + 3 H₂O
How many moles of iron (Fe) can be made from 3.0 moles of Fe₂O₃?
(a) / (b) x (c) = (d) mol Fe

4 Al + 3 O₂ → 2 Al₂O₃
How much mass of aluminum (Al) would be needed to completely react with 45.00 g of oxygen (O₂)?
(a) x 4 = 108 g 16 x 6 = 96 g
(b) ÷ (c) x (d) = (e) g

2 Al + 3 H₂SO₄ → 1 Al₂(SO₄)₃ + 3 H2
How many grams of aluminum sulfate (Al₂(SO₄)₃) would be formed if 250.0 g sulfuric acid (H₂SO₄) completely reacted with aluminum?
(27x2) + ( (a) x3) + (16x12) = 342 g (1x6) + (32x3) + (16x12) = 294 g
(b) ÷ (c) x (d) = (e) g

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Stoichiometry

15 questions

1 N2 + 3 H2 → 2NH3How many moles of hydrogen, H2, are needed to react with 2.00 mol of nitrogen, N2?​ (a) mol N2 ÷ ​ (b) mol N2 x ​ (c) mol H2 = ​ (d) mol H2

2H2 + O2 → 2H2OHow many moles of water, H2O, can be produced if 8.00 moles of H2 are used? (Show your work and answer)

3 Mg + 1 Fe2O3 → 3 MgO + 2 FeIdentify the mole ratios for the following pairs:​ ​ ​ (a) Mg : ​ (b) Fe​ (c) Fe2O3 : ​ (d) Fe​ 1 Fe2O3 : ​ (e) MgO

1 Cl2 + 2 KBr → 1 Br2 + 2 KClHow many grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide (KBr)?​ (a) + 35 = 74g x 2 = 148g 39 + ​80 = ​ (b) g x 2 = 238g​ (c) / ​ (d) x 148 = ​ (e) g

1 CH4 + 2 O2 → 1 CO2 + 2 H2OHow many moles of carbon dioxide (CO2) are produced from the combustion of 110.0 g of CH4 (molar mass = 16 g)?

1 B2H5 + 3 O2 → 2 HBO2 + 2 H2OWhat mass of O2 will be needed to burn 36.1 g of B2H5?16 x 2 = ​ (a) x 3 = 96 g (11 x 2) + (1 x 5) = 27 g​ (b) / ​ (c) x ​ (d) = ​ (e) g

Balance the following reaction: ​ (a) CaC2 + ​ (b) H2O → ​ (c) C2H2 + ​ (d) Ca(OH)2

1 Fe2O3 + 3H2 → 2 Fe + 3 H2OHow many moles of iron (Fe) can be made from 3.0 moles of Fe2O3?​ (a) / ​ (b) x ​ (c) = ​ (d) mol Fe

4 Al + 3 O2 → 2 Al2O3How much mass of aluminum (Al) would be needed to completely react with 45.00 g of oxygen (O2)?​ (a) x 4 = 108 g 16 x 6 = 96 g​ (b) ÷ ​ (c) x ​ (d) = ​ (e) g

2 Al + 3 H2SO4 → 1 Al2(SO4)3 + 3 H2How many grams of aluminum sulfate (Al2(SO4)3) would be formed if 250.0 g sulfuric acid (H2SO4) completely reacted with aluminum?(27x2) + (​ (a) x3) + (16x12) = 342 g (1x6) + (32x3) + (16x12) = 294 g​ (b) ÷ ​ (c) x ​ (d) = ​ (e) g

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1 N₂ + 3 H₂ → 2NH₃
How many moles of hydrogen, H₂, are needed to react with 2.00 mol of nitrogen, N₂?
(a) mol N₂ ÷ (b) mol N₂ x (c) mol H₂ = (d) mol H₂

2H₂ + O₂ → 2H₂O
How many moles of water, H₂O, can be produced if 8.00 moles of H₂ are used? (Show your work and answer)

3 Mg + 1 Fe₂O₃ → 3 MgO + 2 Fe
Identify the mole ratios for the following pairs:
(a) Mg : (b) Fe
(c) Fe₂O₃ : (d) Fe
1 Fe₂O₃ : (e) MgO

1 Cl₂ + 2 KBr → 1 Br₂ + 2 KCl
How many grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide (KBr)?
(a) + 35 = 74g x 2 = 148g 39 + 80 = (b) g x 2 = 238g
(c) / (d) x 148 = (e) g

1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
How many moles of carbon dioxide (CO₂) are produced from the combustion of 110.0 g of CH₄ (molar mass = 16 g)?

1 B₂H₅ + 3 O₂ → 2 HBO₂ + 2 H₂O
What mass of O₂ will be needed to burn 36.1 g of B₂H₅?
16 x 2 = (a) x 3 = 96 g (11 x 2) + (1 x 5) = 27 g
(b) / (c) x (d) = (e) g

Balance the following reaction:
(a) CaC₂ + (b) H₂O → (c) C₂H₂ + (d) Ca(OH)₂

1 Fe₂O₃ + 3H₂ → 2 Fe + 3 H₂O
How many moles of iron (Fe) can be made from 3.0 moles of Fe₂O₃?
(a) / (b) x (c) = (d) mol Fe

4 Al + 3 O₂ → 2 Al₂O₃
How much mass of aluminum (Al) would be needed to completely react with 45.00 g of oxygen (O₂)?
(a) x 4 = 108 g 16 x 6 = 96 g
(b) ÷ (c) x (d) = (e) g

2 Al + 3 H₂SO₄ → 1 Al₂(SO₄)₃ + 3 H2
How many grams of aluminum sulfate (Al₂(SO₄)₃) would be formed if 250.0 g sulfuric acid (H₂SO₄) completely reacted with aluminum?
(27x2) + ( (a) x3) + (16x12) = 342 g (1x6) + (32x3) + (16x12) = 294 g
(b) ÷ (c) x (d) = (e) g