Stoichiometry

1 N₂ + 3 H₂ → 2NH₃

How many moles of hydrogen, H₂, are needed to react with 2.00 mol of nitrogen, N₂?

​ (a)   mol N₂ ÷ ​ (b)   mol N₂ x ​ (c)   mol H₂ = ​ (d)   mol H₂

• 2.00
• 1
• 3
• 6

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112.43.c.9.C

2H₂ + O₂ → 2H₂O

How many moles of water, H₂O, can be produced if 8.00 moles of H₂ are used? (Show your work and answer)

Mathematical Equivalence

ON

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112.43.c.9.C

3 Mg + 1 Fe₂O₃ → 3 MgO + 2 Fe

Identify the mole ratios for the following pairs:

​ ​ ​ (a)   Mg : ​ (b)   Fe

​ (c)   Fe₂O₃ : ​ (d)   Fe

​ 1 Fe₂O₃ : ​ (e)   MgO

• 3
• 2
• 1

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112.43.c.9.C

1 Cl₂ + 2 KBr → 1 Br₂ + 2 KCl

How many grams of potassium chloride (KCl) can be produced from 356 g of potassium bromide (KBr)?

​ (a)   + 35 = 74g x 2 = 148g 39 + ​80 = ​ (b)   g x 2 = 238g

​ (c)   / ​ (d)   x 148 = ​ (e)   g

• 39
• 119
• 356
• 238
• 221

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112.43.c.9.C

1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O

How many moles of carbon dioxide (CO₂) are produced from the combustion of 110.0 g of CH₄ (molar mass = 16 g)?

• 13.7 mol

• 2.75 mol

• 6.85 mol

• 6.11 mol

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112.43.c.9.C

1 B₂H₅ + 3 O₂ → 2 HBO₂ + 2 H₂O

What mass of O₂ will be needed to burn 36.1 g of B₂H₅?

16 x 2 = ​ (a)   x 3 = 96 g (11 x 2) + (1 x 5) = 27 g

​ (b)   / ​ (c)   x ​ (d)   = ​ (e)   g

• 32
• 36.1
• 27
• 96
• 128.356

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112.43.c.9.C

Balance the following reaction:

​ (a)   CaC₂ + ​ (b)   H₂O → ​ (c)   C₂H₂ + ​ (d)   Ca(OH)₂

• 1
• 2

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112.43.c.9.C

1 Fe₂O₃ + 3H₂ → 2 Fe + 3 H₂O

How many moles of iron (Fe) can be made from 3.0 moles of Fe₂O₃?

​ (a)   / ​ (b)   x ​ (c)   = ​ (d)   mol Fe

• 3.0
• 1
• 2
• 6

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112.43.c.9.C

4 Al + 3 O₂ → 2 Al₂O₃

How much mass of aluminum (Al) would be needed to completely react with 45.00 g of oxygen (O₂)?

​ (a)   x 4 = 108 g 16 x 6 = 96 g

​ (b)   ÷ ​ (c)   x ​ (d)   = ​ (e)   g

• 27
• 45.00
• 96
• 108
• 50.625

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112.43.c.9.C

2 Al + 3 H₂SO₄ → 1 Al₂(SO₄)₃ + 3 H2

How many grams of aluminum sulfate (Al₂(SO₄)₃) would be formed if 250.0 g sulfuric acid (H₂SO₄) completely reacted with aluminum?

(27x2) + (​ (a)   x3) + (16x12) = 342 g (1x6) + (32x3) + (16x12) = 294 g

​ (b)   ÷ ​ (c)   x ​ (d)   = ​ (e)   g

• 32
• 250.0
• 294
• 342
• 290.81

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112.43.c.9.C