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Quadratic Functions

Authored by Loryn Yockey

Mathematics

9th - 12th Grade

CCSS covered

Used 28+ times

Quadratic Functions
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18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What are the zeros on the graph?

x= ​ (a)  

x=​ (b)  

x=3

x=0

x=1

x=3

x=-3

x=-1

x=-1

x=-1

x=2

Tags

CCSS.HSF-IF.C.7A

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the solutions to the function f(x)=(x−12)(x+4)f\left(x\right)=\left(x-12\right)\left(x+4\right)

-12 and 4

12 and -4

1/12 and 1/4

-48

Tags

CCSS.HSA-REI.B.4B

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Name the quadratic roots of the function: g(x)=x2−10x+9g\left(x\right)=x^2-10x+9

x= ​ ​

x=​

x=1

x=9

x=-9

x=-1

x=-10

x=10

x=-9

x=10

x=-19

x=1

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

How many solutions does the quadratic function have?

One solution

two solutions

no solution

three solutions

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the following equation linear, exponential, or quadratic?​

f(x)=4x−3f\left(x\right)=4^x-3

​

exponential

linear

quadratic

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Taivon says that the solutions to the function f(x)=(x−3)(x+5) f\left(x\right)=\left(x-3\right)\left(x+5\right)\ are x=-3 and x=5. Which choice explains the reasoning behind Taivon's mistake?

Taivon isn't wrong. The zeros are x=-3 and x=5.

Taivon was supposed to foil the problem to find the zeros.

Taivon is wrong because every solution to a quadratic function should be positive.

Taivon is wrong because each quantity should be set equal to zero; x=3 and x=-5

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the following equation linear, exponential, or quadratic?​

g(x)=3x2+8xg\left(x\right)=3x^2+8x

​

quadratic

linear

exponential

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