What is the acid dissociation reaction for HF dissolving in water?

HF + H2O $$\leftrightarrow$$ F - + H 3 O +

HF + H2O $$\leftrightarrow$$ F + H 3 O

HF + H2O $$\leftrightarrow$$ H 2 F + + OH -

Write the Ka expression for the following reaction: HCN(aq) + H 2 O(l) $$\leftrightarrow$$ CN - (aq) + H 3 O + (aq)

Ka = [HCN][H 2 O] / [CN - ][H 3 O + ]

Ka = [CN - ][H 3 O + ] / [HCN][H 2 O]

Write the acid dissociation expression, Ka, for this reaction: H 3 BO 3 (aq) + H 2 O (l) ↔ H 2 BO 3 - (aq) + H 3 O + (aq)

Ka = $$\frac{\left[H_2BO_3^-\right]\left[H_3O^+\right]}{\left[H_3BO_3\right]}$$

Ka = $$\frac{\left[H_2BO_3^-\right]\left[H_3O^+\right]}{\left[H_3BO_3\right]\left[H_2O\right]}$$

Ka = $$\frac{\left[H_3BO_3\right]}{\left[H_2BO_3^-\right]\left[H_3O^+\right]}$$

Ka = $$\frac{\left[H_3BO_3\right]\left[H_2O\right]}{\left[H_2BO_3^-\right]\left[H_3O^+\right]}$$

[H 3 BO 3 ][H 2 O] = [B 2 BO 3 - ][H 3 O + ]

Write the acid dissociation expression, Ka, for this reaction: HClO 2 (aq) + H 2 O (l) ↔ ClO 2 - (aq) + H 3 O + (aq)

Ka = $$\frac{\left[ClO_2^-\right]\left[H_3O^+\right]}{\left[HClO_2\right]}$$

Ka = $$\frac{\left[ClO_2^-\right]\left[H_3O^+\right]}{\left[HClO_2\right]\left[H_2O\right]}$$

Ka = $$\frac{\left[HClO_2\right]}{\left[ClO_2^-\right]\left[H_3O^+\right]}$$

Ka = $$\frac{\left[HClO_2\right]\left[H_2O\right]}{\left[ClO_2^-\right]\left[H_3O^+\right]}$$

[HClO 2 ][H 2 O] = [ClO 2 - ][H 3 O + ]

Write the acid dissociation expression, Ka, for this reaction: HCl (aq) + H 2 O (l) → Cl - (aq) + H 3 O + (aq)

Ka = $$\frac{\left[Cl^-\right]\left[H_3O^+\right]}{\left[HCl\right]}$$

Ka = $$\frac{\left[Cl^-\right]\left[H_3O^+\right]}{\left[HCl\right]\left[H_2O\right]}$$

Ka = $$\frac{\left[HCl\right]}{\left[Cl^-\right]\left[H_3O^+\right]}$$

Ka = $$\frac{\left[HCl\right]\left[H_2O\right]}{\left[Cl^-\right]\left[H_3O^+\right]}$$

[HCl][H 2 O] = [Cl - ][H 3 O + ]

Honors Chem Ch 14

Quiz

•

Chemistry

•

10th Grade

•

Practice Problem

•

Easy

•

NGSS

HS-PS1-2, MS-PS1-1

Standards-aligned

Abbey Zaepfel

Used 22+ times

FREE Resource

64 questions

Show all answers

1.

FILL IN THE BLANK QUESTION

3 mins • 1 pt

What is the pH of a 0.72 M HBr solution?
(type the answer like this: 0.???
With a zero to the left of the decimal and 3 digits after the decimal)

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

What is the pOH of a solution that has a pH of 3.98?

10.02

1.05 x 10^-4

9.55 x 10^-11

3.98

3.

MATCH QUESTION

3 mins • 1 pt

Label the following as acid or base, or conjugate acid or conjugate base.
HCl + NH₃ --> Cl^- + NH₄⁺

base

Cl^-

acid

HCl

conjugate base

NH₄⁺

conjugate acid

NH₃

4.

MATCH QUESTION

3 mins • 1 pt

Label the following as either acid or base or conjugate acid or conjugate base:
HClO + CH₃NH₂ --> ClO^- + CH₃NH₃⁺

conjugate base

HClO

base

ClO^-

conjugate acid

CH₃NH₃⁺

acid

CH₃NH₂

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

What is the name of this compound: HNO₃

nitric acid

nitrous acid

hydronitric acid

hydronitrous acid

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

What is the name of this compound: H₂SO₃

sulfuric acid

sulfurous acid

hydrosulfurous acid

hydrosulfate acid

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

What is the name of this compound: HBr

bromic acid

broumous acid

hydrobromic acid

hydrobromous acid

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Honors Chem Ch 14

64 questions

What is the pH of a 0.72 M HBr solution?
(type the answer like this: 0.???
With a zero to the left of the decimal and 3 digits after the decimal)

What is the pOH of a solution that has a pH of 3.98?

Label the following as acid or base, or conjugate acid or conjugate base.
HCl + NH₃ --> Cl^- + NH₄⁺