Review Unit 2 Solving Equations

In the equation

x + 7 = 12

7 is being added to the variable, x.

How should you show your work to isolate the variable and solve the equation?

• Subtract 7 from both sides. The solution is x = 5.

• Add 7 to both sides.

  The solution is x = 19.

• Multiply both sides by 7 The solution is x = 84.

Tags

CCSS.6.EE.B.7

• Divide both sides by 11

• Multiply both sides by 11.

• Add 11 to both sides.

• Subtract 11 to both sides.

Tags

CCSS.HSA.REI.A.1

Solve for x in the following equation:

x + 7 = 12

• x = 5

• x = 19

• x = 4

• x = 84

Tags

CCSS.6.EE.B.7

Solve for p in the following equation:

4p = 16

• p = 12

• p = 64

• p = 3

• p = 4

Tags

CCSS.6.EE.B.7

What is the solution of 6d = 24

• d = 4

• d = 5

• d = 18

• d = 144

Tags

CCSS.6.EE.B.7

Solve for x:

• x = 20
• x = 7
• x = 10
• x = 3

Tags

CCSS.6.EE.B.7

3c + 5 = 23

• c = 3
• c = 6
• c = 7
• c = 18

Tags

CCSS.7.EE.B.4A

The steps in solving 5b - 6 = 24 are: 

• Add 6 to both sides and divide both sides by 5
• Add 6 to both sides and multiply both sides by 5
• Subtract 6 from both sides then multiply both sides by 5
• Subtract 6 from both sides then divide both sides by 5

Tags

CCSS.7.EE.B.4A

Solve the equation. 

• -90
• 90
• -40
• -180

Tags

CCSS.6.EE.B.7

Solve for z in the following equation:

z - 33 = 147

• z= 114

• z = 177

• z = 180

• No Solution

Tags

CCSS.6.EE.B.7