ITN Modules 11-13

An administrator must send a message to everyone on the router A network. What is the broadcast address for network 172.16.16.0/22?

• 172.16.16.255

• 172.16.20.255

• 172.16.19.255

• 172.16.23.255

• 172.16.255.255

Answer explanation

The 172.16.16.0/22 network has 22 bits in the network portion and 10 bits in the host portion. Converting the network address to binary yields a subnet mask of 255.255.252.0. The range of addresses in this network will end with the last address available before 172.16.20.0. Valid host addresses for this network range from 172.16.16.1-172.16.19.254, making 172.16.19.255 the broadcast address.

Considering the addresses already used and having to remain within the 10.16.10.0/24 network range, which subnet address could be assigned to the network containing 25 hosts?

• 10.16.10.160/26

• 10.16.10.128/28

• 10.16.10.64/27

• 10.16.10.224/26

• 10.16.10.240/27

Answer explanation

Addresses 10.16.10.0 through 10.16.10.63 are taken for the leftmost network. Addresses 10.16.10.192 through 10.16.10.207 are used by the center network.The address space from 208-255 assumes a /28 mask, which does not allow enough host bits to accommodate 25 host addresses.The address ranges that are available include 10.16.10.64/26 and10.16.10.128/26. To accommodate 25 hosts, 5 host bits are needed, so a /27 mask is necessary. Four possible /27 subnets could be created from the available addresses between 10.16.10.64 and 10.16.10.191:10.16.10.64/2710.16.10.96/2710.16.10.128/2710.16.10.160/27

Match the network with the correct IP address and prefix that will satisfy the usable host addressing requirements for NETWORK A

• 192.168.0.96 /27

• 192.168.0.128 /25

• 192.168.0.80 /30

• 192.168.0.0 /26

Answer explanation

Network A needs to use 192.168.0.128 /25, which yields 128 host addresses.

Match the network with the correct IP address and prefix that will satisfy the usable host addressing requirements for NETWORK B

• 192.168.0.96 /27

• 192.168.0.128 /25

• 192.168.0.80 /30

• 192.168.0.0 /26

Answer explanation

Network B needs to use 192.168.0.0 /26, which yields 64 host addresses.

Match the network with the correct IP address and prefix that will satisfy the usable host addressing requirements for NETWORK C

• 192.168.0.96 /27

• 192.168.0.128 /25

• 192.168.0.80 /30

• 192.168.0.0 /26

Answer explanation

Network C needs to use 192.168.0.96 /27, which yields 32 host addresses.

What is the prefix length notation for the subnet mask 255.255.255.224?

• /25
• /26
• /27
• /28

How many valid host addresses are available on an IPv4 subnet that is configured with a /26 mask?

• 254
• 190
• 192
• 62
• 64

Which subnet mask would be used if 5 host bits are available?

• 255.255.255.0
• 255.255.255.128
• 255.255.255.224​
• 255.255.255.240

A network administrator subnets the 192.168.10.0/24 network into subnets with /26 masks. How many equal-sized subnets are created?

• 2
• 4
• 8
• 16
• 64

An administrator wants to create four subnetworks from the network address 192.168.1.0/24. What is the network address and subnet mask of the second useable subnet?

• subnetwork 192.168.1.64 subnet mask 255.255.255.192
• subnetwork 192.168.1.32 subnet mask 255.255.255.240
• subnetwork 192.168.1.64 subnet mask 255.255.255.240
• subnetwork 192.168.1.128 subnet mask 255.255.255.192
• subnetwork 192.168.1.8 subnet mask 255.255.255.224