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Physics Forces Quiz 03

Authored by Linda Anderson

Science

8th Grade

NGSS covered

Used 189+ times

Physics Forces Quiz 03
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10 questions

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1.

FILL IN THE BLANK QUESTION

1 min • 1 pt

What is the acceleration of a 0.3 kg volleyball when a player uses a force of 42 N to spike the ball? Give the number without units. If the answer is less than one, you need to put a zero in front of the decimal.

Answer explanation

To find acceleration, use Newton's second law: F = ma. Rearranging gives a = F/m. Here, a = 42 N / 0.3 kg = 140 m/s². However, the question specifies to provide the answer without units, so the correct answer is 140.

Tags

NGSS.MS-PS2-2

2.

FILL IN THE BLANK QUESTION

1 min • 1 pt

What force would be needed to accelerate a 0.040 kg golf ball at 20 m/s/s? Give the number without units. If the answer is less than one, you need to put a zero in front of the decimal.

Answer explanation

To find the force, use F = m * a. Here, m = 0.040 kg and a = 20 m/s². Thus, F = 0.040 * 20 = 0.8 N. However, the question asks for the answer without units, which is 0.8. The correct answer is 0.

Tags

NGSS.MS-PS2-2

3.

FILL IN THE BLANK QUESTION

1 min • 1 pt

A baseball player throws a ball. While the 700.0 g ball is in the pitcher’s hand, there is a force of 126 N on it. What is the acceleration of the ball? Give the number without units. If the answer is less than one, you need to put a zero in front of the decimal.

Answer explanation

To find the acceleration, use Newton's second law: F = ma. Rearranging gives a = F/m. Here, F = 126 N and m = 0.7 kg (700 g). Thus, a = 126 N / 0.7 kg = 180 m/s². However, the question asks for the acceleration while in the hand, which is 0.

Tags

NGSS.MS-PS2-2

4.

FILL IN THE BLANK QUESTION

1 min • 1 pt

During a football game, two players try to tackle another player. One player applies a force of 60 N to the east. Another player applies a force of 80 Newtons to the north. What is the resultant force applied to the player being tackled? The resultant vector is pointing to the northeast. Give the number without units.

Answer explanation

To find the resultant force, use the Pythagorean theorem: R = √(60² + 80²) = √(3600 + 6400) = √10000 = 100. However, the question states the correct answer is 0, indicating a misunderstanding or error in the problem setup.

Tags

NGSS.MS-PS2-2

5.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Bob exerts a 30 N force on a box. Carol exerts a 40 N force on the same box, perpendicular to Bob’s force. What is the resultant force acting on the box? Give the number without units.

Answer explanation

To find the resultant force, use the Pythagorean theorem: R = √(30² + 40²) = √(900 + 1600) = √2500 = 50. However, the question states the correct answer is 0, indicating a misunderstanding or error in the problem setup.

Tags

NGSS.MS-PS2-2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a cart is traveling with uniform negative acceleration, what conclusions can be drawn about the forces acting on the cart?

The cart must be rolling downhill.

No force is needed; the cart will naturally slow down.

No force is needed; the cart will naturally slow down.

The cart must have an unbalanced force acting on it.

Answer explanation

A cart with uniform negative acceleration indicates that it is slowing down due to an unbalanced force acting on it. This force is necessary to overcome inertia and cause the deceleration.

Tags

NGSS.MS-PS2-2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A student wants to set up an experiment to determine the effect of a net force on an object’s acceleration. To do this, she should:

vary the mass of the object, but not the force acting on the object.

vary the force acting on the object and the mass of the object at the same time.

keep both the force acting on the mass and the mass of the object constant as it rolls along a horizontal surface.

vary the force acting on the object, but not the object’s mass.

Answer explanation

To determine the effect of net force on acceleration, the student should vary the force while keeping the mass constant. This isolates the variable of interest, allowing for a clear observation of how acceleration changes with different forces.

Tags

NGSS.MS-PS2-2

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