Simple Harmonic Motion

A particle starts S.H.M from the mean position. Its amplitude is A and time period is T. At the time when its speed is half of the maximum speed is half of the maximum speed, its displacement y is

• A/2
• A/√2
• A √3/2
• 2A/√3

Two equations of two S.H.M are y = a sin (ω t – α )and y = b cos (ω t – α ). The phase difference between the two is

• 0 degree
• α degree
• 90 degree
• 180 degree

A body is executing simple harmonic motion with an angular frequency 2rad/s. The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm, is

• 40 mm/s
• 60 mm/s
• 113 mm/s
• 120 mm/s

A simple harmonic oscillator has a period of 0.01 sec and an amplitude of 0.2 m. the magnitude of the velocity in m sec-1 at the centre of oscillator is

• 20 π
• 100
• 40 π
• 100 π

A particle executes S.H.M with a period of 6 second and amplitude of 3 cm. Its maximum speed in cm/sec is

• π/2
• π
• 2π
• 3π

The displacement of a particle moving in S.H.M at any instant is given by y = a sin ωt .The acceleration after time t = T/4 is (where T is the time period )

• a ω
• - a ω
• a ω2
• -a ω2

A particle executes simple harmonic motion along a straight line with an amplitude A. The potential energy is maximum when the displacement is

• ±A
• Zero
• ±A/2
• ±A/√2

A particle is vibrating in a simple harmonic motion with an amplitude of 4 cm. At what displacement from the equilibrium position, is its energy half potential and half kinetic

• 1 cm
• √2 cm
• 3 cm
• 2 √2 cm

The potential energy of a particle executing S.H.M. is 2.5 J. when its displacement is half of amplitude is half of amplitude .The total energy of the particle be

• 18 J
• 10 J
• 12 J
• 2.5 J

The amplitude of a particle executing SHM is made three- fourth keeping its time period constant. Its total energy will be

• E/2
• ¾ E
• 19/16 E
• None of these