End of Week 2 Recap

(2x³ + 5x² + 9) ÷ (x + 3)

• 2x² - x + 3
• 2x³ - x² + 3x
• 2x² + 11x + 33 + 108/x+3
• 2x² - 5x + 12

-2x²+4x+48 ÷ x+4

• -2x+12
• 2x+12
• -4x+9
• 4x+9

Use synthetic division:
(2x³ - 5x - 7) ÷ (x - 2)

• 2x³ - 4x² + 3x - 13
• 2x³ + 4x² +3x - 1
• 2x² - 4x + 3 - 13/x-2
• 2x² + 4x + 3 - 1/x-2

Factor:

Factor
27x³-64

• (3x-4)(9x²+12x+16)
• (3x-4)(9x²-12x+16)
• (3x+4)(9x²-12x+16)
• (3x+4)(9x²+12x+16)

Factor completely.
k² -2k - 24

• (k+4)(k-6)
• (k+4)(k+6)
• (k+6)(k-1)
• (k-4)(k+6)

Factor completely: 2x²+22x+60

• (2x+10)(x+6)
• (x+5)(x+6)
• 2(x+1)(x+30)
• 2(x+5)(x+6)

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5

• x = 20 and x = -9

• x = 4 and x = 5

• x = -4 and x = 5

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

h(x) = -4x + 3

g(x) = 4x - 2

Find h(g(6))

• -107

• 107

• -85

• 85