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六年级数学 钱币 成本、售价、盈亏

Authored by WINNIE Moe

Mathematics

6th Grade

Used 1+ times

六年级数学 钱币 成本、售价、盈亏
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5 questions

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1.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

一台笔记型电脑的成本是RM2150.40,售价则是RM2399.90。计算售卖这台笔记型电脑的盈利。

(a)  

2.

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

3件相同的衣服售价共RM107.70。小贩卖出这三件衣服后,获得RM31.20的盈利。计算一件衣服的成本。

(a)  

3.

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

一辆汽车的成本是RM38000。汽车代理商售卖这辆汽车所获得的盈利占成本的10%。计算这辆汽车的售价。

(a)  

Answer explanation

一辆汽车成本

= RM38000

一辆汽车的盈利

= 成本的10%

= RM38000 X 10%

= RM3800

一辆汽车的售价

= 成本 + 盈利

= RM38000 + RM3800

= RM41800

4.

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

一家工厂在上半年的收入是RM185600,开支是RM179000。这家工厂在下半年的收入是RM197400,开支是RM218500。这家工厂在这一年亏了多少钱?

(a)  

5.

FILL IN THE BLANKS QUESTION

10 mins • 1 pt

肖老板以RM9800购买了1000件潮流衬衫。他售卖了一半的衬衫后,共获得RM4450的盈利。每件衬衫的售价是多少?

(a)  

Answer explanation

1000件衬衫 = RM9800

一件衬衫

= RM9800 ÷ 1000

= RM9.80

卖了一半的衬衫(500件)= 盈利RM4450

一件衬衫的盈利

= RM4450 ÷ 500

= RM 8.90

一件衣服的售价

= 成本 + 盈利

= RM 9.80 + RM8.90

= RM 18.70

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