Ksp quiz

The Solubility product for a saturated solution of Ca₃(PO₄)₂ is

• K_sp = [Ca²⁺][PO₄^3-]

• K_sp = [3Ca²⁺][2PO₄^3-]

• K_sp = [Ca²⁺]³[PO₄^3-]²

• K_sp = [3Ca²⁺]³[2PO₄^3-]²

What is the Solubility product for an ionic compound of BaSO₄ ?

• K_sp= [Ba²⁺][SO₄^2-]

• K_sp= [Ba²⁺][4SO₄^2-]⁴

• K_sp= [Ba²⁺][4SO₄^2-]

• K_sp= [2Ba²⁺][4SO₄^2-]

The solubility of silver sulphide is 5.0 x 10^-17 mol dm^-3. Calculate its solubility product.

• K_sp = 5 x 10⁴⁹

• K_sp = 5 x 10³³

• K_sp = 5 x 10^-49

• K_sp = 5 x 10^-33

The solubility product of silver chromate (VI) at room temperature is 2.4 x 10^-12. Calculate the solubility of Ag⁺_(aq) and CrO₄^2-_(aq) ions in a saturated solution of silver chromate (VI) at room temperature.

• [Ag⁺] = 1.68 x 10⁴ M and [CrO₄^2- ]= 8.4 x 10^-5 M

• [Ag⁺ ]= 1.68 x 10⁴ M and [CrO₄^2- ]= 8.4 x 10⁵ M

• [Ag⁺ ]= 1.68 x 10^-4 M and [CrO₄^2- ]= 8.4 x 10⁵ M

• [Ag⁺ ]= 1.68 x 10^-4 M and [CrO₄^2- ]= 8.4 x 10^-5 M

The K_sp value for PbF₂ is 4 x 10^-8 . Calculate the solubility of solid PbF₂ in a 0.5 mol dm^-3 NaF solution.

• 8 x 10⁸

• 1.6 x 10⁷

• 8 x 10^-8

• 1.6 x 10^-7

The solubility product of calcium chlorate, Ca(ClO₃)₂ is 7.1 x 10^-7 at 25 ^oC. How many grams of Ca(ClO₃)₂ were dissolved in 750 cm³?

• 3.61 x 10⁵ g

• 2.03 x 10^-5 g

• 8.72 x 10^-1 g

• 3.61 x 10^-5 g