
ULANGAN UJIAN SETARA 2
Authored by Basirah Bakar
Chemistry
10th - 11th Grade
Used 21+ times

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28 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Antara berikut, yang manakah formula kimia yang betul bagi sebatian?
Which of the following chemical formulae for compounds is correct?
A
B
C
D
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Pasangan yang manakah menunjukkan ion dan formula ionnya dengan betul?
Which pair shows the ion and its ionic formula correctly?
A
B
C
D
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Formula kimia bagi kuprum (I) oksida ialah?
Chemical formula of copper (I) oxide is?
A
B
C
D
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Logam X membentuk sebatian oksida dengan formula kimia X2O. Jika formula bagi ion manganate (VII) ialah MnO4-, apakah formula kimia manganate bagi X?
Metal X forms an oxide compound with the chemical formula of X2O. If the formula of manganate (VII) ion is MnO4-, what is the chemical formula of manganate of X?
Logam X membentuk sebatian oksida dengan formula kimia X2O. Jika formula bagi ion manganate (VII) ialah MnO4-, apakah formula kimia manganate bagi X?
Metal X forms an oxide compound with the chemical formula of X2O. If the formula of manganate (VII) ion is MnO4-, what is the chemical formula of manganate of X?
A
B
C
D
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Antara berikut, yang manakah logam X?
Which of the following is metal X?
Zink
Zinc
Kuprum
Copper
Magnesium
Magnesium
Alumina
Aluminium
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Antara berikut, logam manakah boleh menggantikan magnesium?
Which of the following metal can replace magnesium?
Natrium
Sodium
Zink
Zinc
Plumbum
Lead
Stanum
Tin
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
2.7 g unsur X bertindak balas dengan 2.4 g unsur Y untuk membentuk sebatian dengan formula empiric X2Y3. Berapakah jisim atom relatif bagi Y? [Jisim atom relatif: X=27]
2.7 g of element X reacts with 2.4 g of element Y to form a substance with the empirical formula of X2Y3. What is the relative atomic mass of Y? [Relative atomic mass: X=27]?
2.7 g unsur X bertindak balas dengan 2.4 g unsur Y untuk membentuk sebatian dengan formula empiric X2Y3. Berapakah jisim atom relatif bagi Y? [Jisim atom relatif: X=27]
2.7 g of element X reacts with 2.4 g of element Y to form a substance with the empirical formula of X2Y3. What is the relative atomic mass of Y? [Relative atomic mass: X=27]?
8
16
24
31
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