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lesson2

Authored by MAJDI MATH

Mathematics

12th Grade

Used 1+ times

lesson2
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

g ′(x)=g\ '\left(x\right)= إذا علمت أنّ g(x)=xe.exg\left(x\right)=x^e.e^x فإنّ

e(x+1)x(e−1)e^{\left(x+1\right)}x^{\left(e-1\right)}

xe.ex+e(x−1)x^e.e^x+e^{\left(x-1\right)}

xe.ex(1+ex)x^e.e^x\left(1+\frac{e}{x}\right)

x(e−1)exx^{\left(e-1\right)}e^x

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

إذا علمت أنّ y=sin⁡x(1+cot⁡x)y=\sin x\left(1+\cot x\right) حيث x∈(0  ,  π )x\in\left(0\ \ ,\ \ \pi\ \right) فإنّ قيم xx التي يكون عندها للاقتران مماس أفقي

π6\frac{\pi}{6}

3π4\frac{3\pi}{4}

π4\frac{\pi}{4}

π3\frac{\pi}{3}

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x)=(x2+2x)(2x3−1)   ,  f′(x)=?f(x)=\left(x^2+2x\right)\left(2x^3-1\right)\ \ \ ,\ \ f'\left(x\right)=?

10x4+16x3−2x−210x^4+16x^3-2x-2

10x4+16x3−2x+210x^4+16x^3-2x+2

24x2+24x24x^2+24x

10x4+1010x^4+10

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

x=π3x=\frac{\pi}{3} إذا كان f(x)=sec⁡x+1sec⁡x−1f\left(x\right)=\frac{\sec x+1}{\sec x-1} فإنّ معادلة العمودي على المماس عند

y=−14 3x−π12 3+3y=\frac{-1}{4\ \sqrt[]{3}}x-\frac{\pi}{12\ \sqrt[]{3}}+3

y=14 3x+π12 3+3y=\frac{1}{4\ \sqrt[]{3}}x+\frac{\pi}{12\ \sqrt[]{3}}+3

y=14 3x−π12 3−3y=\frac{1}{4\ \sqrt[]{3}}x-\frac{\pi}{12\ \sqrt[]{3}}-3

y=14 3x−π12 3+3y=\frac{1}{4\ \sqrt[]{3}}x-\frac{\pi}{12\ \sqrt[]{3}}+3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

d3ydx3=?\frac{d^3y}{dx^3}=? إذا كان y=x2+1x3y=x^2+\frac{1}{\sqrt[3]{x}} فإنّ

x6+1xx^6+\frac{1}{x}

−2827 x103-\frac{28}{27\ \sqrt[3]{x^{10}}}

−2827x310-\frac{28}{27\sqrt[10]{x^3}}

−2827x3\frac{-28}{27\sqrt[3]{x}}

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f′′′(x)+f′(x)= ??f'''\left(x\right)+f'\left(x\right)=\ ?? إذا كان f(x)=x2cos⁡xf\left(x\right)=x^2\cos x فإن

4xcos⁡x−6sin⁡x4x\cos x-6\sin x 4xcos⁡x+6sin⁡x4x\cos x+6\sin x

−4xcos⁡x+6sin⁡x-4x\cos x+6\sin x

−4xcos⁡x−6sin⁡x-4x\cos x-6\sin x

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

يتكاثر مجتمع بكتيري حسب العلاقة p(t)=ett+1p\left(t\right)=\frac{e^t}{t+1} حيث pp تمثل عدد البكتريا بالمئات و t  t\ \ الزمن بالثواني فإن معدل تغير عدد البكتريا بالنسبة للزمن عندما t=4s t=4s\ ا

4et10\frac{4e^t}{10}

6et10\frac{6e^t}{10}

0

4e425\frac{4e^4}{25}

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