Section 8.4 and 8.5 Review Work

The following is the result of solving what kind of equation/inequality?

Absolute value A) Equation B) Less than case C) Greater than Case D) Greater than or equal to case. Note: the endpoints (-1,0) and (5, 0) are part of the solution.

• The graph represents the solution of a absolute value equation

• The graph represents the solution of a

  absolute value inequality (less than case)

• The graph represents the solution of a

  absolute value inequality (Greater than case)

• The graph represents the solution of a

  absolute value inequality (Greater or equal too case)

Solve the double inequality

1.1 < 2x - 0.9 <= 2.1

[Note the right hand inequality is a "less than or equal to"]

Answer using interval notation.

• (1, 1.5)

• (10, 15]

• [10, 15)

• (1, 1.5]

Solve the compound inequality and answer in interval notation

7x+ 3 < 5x - 3 and (x/4) + 7 <= 5

• (-inf, - 6)

• (-inf, -8)

• (-inf -6]

• (-inf, -8]

Let C = {-4, -2, 0, 2, 4, 6} and D = {-3, -2, -1, 1, 2, 3}

Find C ⋂ D

• { }

  (the null set, or empty set}

• {-4, -3, -2, -1, 0, 1, 2, 3, 4, 6}

• {-2, 2}

• {-2, 0, 2}

Let C = {-4, -2, 0, 2, 4, 6} and D = {-3, -2, -1, 1, 2, 3}

Find C ⋃ D

• {-4, -3, -2, -1, 0, 1, 2, 3, 4, 6}
• {-4, -2, 0, 2, 4, 6}
• {-3, -2, -1, 1, 2, 3}
• {-4, -3, -2, -1, 0, 1, 2, 3, 4, 6, 8}

Tags

CCSS.HSS.CP.A.1

Solve the absolute value inequality. Answer in interval notation

-|4x-2|< (- 14)

• (-∞, -3) U (4, ∞)

• (-∞, -4] U (3, ∞)

• (-∞, -3] U [4, ∞)

• (-∞, -4) U [3, ∞)

• (-∞, -17/3] ∪ [-7, ∞)

• [-17/3, 7]

• (-∞, -7) ∪ (17/3, ∞)

• (-∞, -7] ∪ [17/3, ∞)

The equation of a line parallel to 8x + 4y = 5, passing through the point (2, 1) would be

• y=2x + 1

• y = (-2)x + 1

• y=2x+5

• y = (-2)x+5