Friction and Ramps Quizizz

Friction and Ramps Quizizz

12th Grade

27 Qs

quiz-placeholder

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Friction and Ramps Quizizz

Friction and Ramps Quizizz

Assessment

Quiz

Physics

12th Grade

Medium

Created by

KELLY DOYLE

Used 2+ times

FREE Resource

27 questions

Show all answers

1.

MATH RESPONSE QUESTION

2 mins • 1 pt

A 6 kg box is sitting at rest. It has a coefficient of static friction of 0.5 and of kinetic friction of 0.2

I push on it with 15 N. What is the acceleration of the box, m/s2?

Mathematical Equivalence

ON

Answer explanation

The maximum static friction is 30 N (normal force of 60 N multiplied by 0.5).

We did not push hard enough to break static friction, so the acceleration and the velocity are zero.

2.

MATH RESPONSE QUESTION

2 mins • 1 pt

A 8 kg box is sitting at rest. It has a coefficient of static friction of 0.4 and of kinetic friction of 0.2

I push on it with 40 N. What is the acceleration of the box, in m/s2?

Mathematical Equivalence

ON

Answer explanation

The maximum static friction is 32 N (normal force of 80 N multiplied by 0.4).

We pushed hard enough to break static friction. SO the box will experience kinetic friction instead. Kinetic friction is 16 N (normal of 80 multiplied by 0.2).

So, if we have a push of 40 N and an opposing kinetic friction of 16 N, our next force is 24 N. Divide that by mass (8 kg) to get 3 m/s2.

3.

MATH RESPONSE QUESTION

2 mins • 1 pt

A 12 kg box is sitting at rest. It has a coefficient of static friction of 0.3 and of kinetic friction of 0.1

I push on it with 20 N. What is the acceleration of the box, in m/s2?

Mathematical Equivalence

ON

Answer explanation

The maximum static friction is 36 N (normal force of 80 N multiplied by 0.4).

We did not push hard enough to make the box move (acceleration and velocity remain zero).

4.

MATH RESPONSE QUESTION

2 mins • 1 pt

A 12 kg box is sitting at rest. It has a coefficient of static friction of 0.3 and of kinetic friction of 0.1

I push on it with 60 N. What is the acceleration of the box, in m/s2?

Mathematical Equivalence

ON

Answer explanation

The maximum static friction is 36 N (normal force of 80 N multiplied by 0.4).

We broke static friction. Recalculate with kinetic friction!

Kinetic friction is 120 N (normal) multiplied by 0.1 (coefficient of kinetic friction) = 12 N

A push of 60 N and opposing friction 12 N results in 48 N as a net force. Divide that by mass for an acceleration of 4 m/s2.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

A box is being pushed across a rough surface and is traveling at a constant speed. What must be true?

It is incurring static friction

Net force is zero

Kinetic friction is greater than applied force

Applied force is greater than kinetic friction

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the net force is zero, then the object's velocity is...

must be zero

decreasing

increasing

not changing

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

A box is sliding up a rough ramp. What direction does friction point?

Down the ramp

Up the ramp

Perpendicular to the ramp

Both up and down the ramp at the same time

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