Synthetic Divsion

(2x³ + 5x² + 9) ÷ (x + 3)

• 2x² - x + 3
• 2x³ - x² + 3x
• 2x² + 11x + 33 + 108/x+3
• 2x² - 5x + 12

Tags

CCSS.HSA.APR.D.6

(3x³ + 5x - 1) ÷ (x + 1)

• 3x³ - 3x² + 8x - 9
• 3x² - 3x + 8 - 9/x+1
• 3x² + 3x + 8 + 7/x+1
• 3x³ + 3x² + 8x + 7

Tags

CCSS.HSA.APR.D.6

Use synthetic division:
(2x³ - 5x - 7) ÷ (x - 2)

• 2x³ - 4x² + 3x - 13
• 2x³ + 4x² +3x - 1
• 2x² - 4x + 3 - 13/x-2
• 2x² + 4x + 3 - 1/x-2

Tags

CCSS.HSA.APR.D.6

For synthetic division, what would be the number in the left hand box?

• 0
• 1
• 2
• 3

Tags

CCSS.HSA.APR.D.6

If you were dividing x⁶ + 4x³ + 2, how many 0's would you need when setting up the top row of your synthetic division?

• 0
• 2
• 4
• 6

Tags

CCSS.HSA.APR.D.6

If you are missing an exponent in your polynomial you must put a zero as a coefficient place holder for that exponent

• True
• False

What is the proper way to write the answer for the following problem?

• 2x³-x²-25x+12

• 2x⁴-x³-25x²-12x+0

• 2x³-x²-25x-12

• 2x⁴-x³-25x²-12x-0

Tags

CCSS.HSA.APR.D.6

            Is (x-2) a factor of             f(x)= x³-8x²+14x-4?

• Yes, (x-2) is a factor. There is a remainder.
• No, (x-2) is  not a factor. The remainder is zero.
• Yes, (x-2) is a factor. The remainder is zero.
• No, (x-2) is  not a factor. There is a remainder. 

Tags

CCSS.HSA.APR.B.2

What should be the order of the polynomial coefficients if
(3x - 4x³ + 6x⁴ + 1) / (x + 3)

• 3   0   -4   6   1
• 6   -4   3   1   0
• 6   -4   0   3   1
• -6   4   0   -3   -1

Tags

CCSS.HSA.APR.D.6

4x⁴+4x³-9x²-x+2 ÷ x-1

• 4x³+8x²-7x-2
• 4x³+19x²-x-2
• 4x³+8x²-x-9
• 4x³+8x²-x-2

Tags

CCSS.HSA.APR.D.6