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12. Электр өрісі

Authored by Сапура Рустемова

Physics

1st Grade

Used 77+ times

12. Электр өрісі
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13 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Электрон зарядының мәні:

е≈1,5⋅10−19 Кле\approx1,5\cdot10^{-19}\ Кл

е≈1,6⋅10−18 Кле\approx1,6\cdot10^{-18}\ Кл

е≈1,6⋅10−19 Кле\approx1,6\cdot10^{-19}\ Кл

е≈1,6⋅10−17 Кле\approx1,6\cdot10^{-17}\ Кл

е≈1,5⋅10−17 Кле\approx1,5\cdot10^{-17}\ Кл

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Беттік тығыздық

ρ=qV\rho=\frac{q}{V}

ρ=Vq\rho=\frac{V}{q}

σ=kqS\sigma=\frac{kq}{S}

σ=Sq\sigma=\frac{S}{q}

σ=qS\sigma=\frac{q}{S}

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Көлемдік тығыздық

ρ=qV\rho=\frac{q}{V}

ρ=Vq\rho=\frac{V}{q}

σ=kqS\sigma=\frac{kq}{S}

σ=Sq\sigma=\frac{S}{q}

σ=qS\sigma=\frac{q}{S}

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Зарядтың сақталу заңы:

q1±q2±...±qn=constq_1\pm q_2\pm...\pm q_n=const

q1+q2−...+qn=constq_1+q_2-...+q_n=const

q1+q2+...+qn=constq_1+q_2+...+q_n=const

q1−q2+...−qn=constq_1-q_2+...-q_n=const

q1−q2−...−qn=constq_1-q_2-...-q_n=const

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Кулон заңы

Fk=∣q1∣⋅∣q2∣r2kF_k=\frac{\left|q_1\right|\cdot\left|q_2\right|}{r^2k}

Fk=k∣q1∣⋅∣q2∣r2F_k=k\frac{\left|q_1\right|\cdot\left|q_2\right|}{r^2}

Fk=r2∣q1∣⋅∣q2∣kF_k=r^2\frac{\left|q_1\right|\cdot\left|q_2\right|}{k}

E→=F→q\overrightarrow{E}=\frac{\overrightarrow{F}}{q}

E→=k∣Q∣r2\overrightarrow{E}=\frac{k\left|Q\right|}{r^2}

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Электр өрісінің кернеулігі

Fk=∣q1∣⋅∣q2∣r2kF_k=\frac{\left|q_1\right|\cdot\left|q_2\right|}{r^2k}

Fk=k∣q1∣⋅∣q2∣r2F_k=k\frac{\left|q_1\right|\cdot\left|q_2\right|}{r^2}

Fk=r2∣q1∣⋅∣q2∣kF_k=r^2\frac{\left|q_1\right|\cdot\left|q_2\right|}{k}

E→=F→q\overrightarrow{E}=\frac{\overrightarrow{F}}{q}

E→=k∣Q∣r2\overrightarrow{E}=\frac{k\left|Q\right|}{r^2}

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Нүктелік зарядтың өріс кернеулігі

Fk=∣q1∣⋅∣q2∣r2kF_k=\frac{\left|q_1\right|\cdot\left|q_2\right|}{r^2k}

Fk=k∣q1∣⋅∣q2∣r2F_k=k\frac{\left|q_1\right|\cdot\left|q_2\right|}{r^2}

Fk=r2∣q1∣⋅∣q2∣kF_k=r^2\frac{\left|q_1\right|\cdot\left|q_2\right|}{k}

E→=F→q\overrightarrow{E}=\frac{\overrightarrow{F}}{q}

E→=k∣Q∣r2\overrightarrow{E}=\frac{k\left|Q\right|}{r^2}

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