
Using Q=mcdeltaT
Authored by Sylvia Welke
Chemistry
12th Grade
NGSS covered
Used 9+ times

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9 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
If the specific heat of water is 4.18 J/g∙°C, how much heat is required to increase the temperature of 1,200 g of water from 23.0 °C to 39.0 °C?
-80.3 J
80.3 J
80.3 kJ
-80.3 kJ
Tags
NGSS.HS-PS3-4
NGSS.HS-PS3-1
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A sample of iron receives 50.0J of heat energy that raises the temperature of the iron by 25.0°C. If iron has a specific heat of 0.10 J/g°C, what is the mass of the iron sample?
125 g
5.00 g
20.0 g
50.0 g
Tags
NGSS.HS-PS3-4
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The specific heat of water is 4.18 J/g°C.
If 980.0 J of energy is added to 6.20 g of water at 18.0 °C, what is the final temperature of the water?
37.8 °C
-19.8 °C
19.8 °C
55.8 °C
Tags
NGSS.HS-PS3-4
NGSS.HS-PS3-1
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
What is the formula to calculate heat energy required to raise the temperature of any substance?
Q = mc∆T
Q = mHv
Q = ½ mv
m = QHf
Tags
NGSS.HS-PS3-4
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
The equation for calculating the energy involved in a substance being heated is Q = mCΔT. The correct expression for calculating ΔT is
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
In heat capacity equations, what does the triangle represent?
Temperature
energy
mass
change in
change in temp
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
How much energy is required to raise 85.36 g of water from 18.5oC to 60.3oC? Assume c = 4.18 J/goC
21500 J
66000 J
14900 J
85400 J
Tags
NGSS.HS-PS3-4
NGSS.HS-PS3-1
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