Algebra 2 9 Weeks/ Cycle 1 Review

Solve:
 |x + 3| > 8

• x > 5 or x < -11
• x > 5
• all real numbers
• no solution

• n > 1 or n < -7
• n > -1 or n < -7
• -7 < n < -1
• no solution

x + 1 ≤ -3 or -4x < -8

• x ≤ -4 or x > 2

• x ≤ -4 and x > 2

• x ≤ -2 or x > 2

• x ≤ -2 and x > 2

3 < 2x + 1 < 7

• 1 < x < 3

• 3 < x < 4

• 3 < x < 3

• 2 < x < 6

26 ≤ 7n + 12 < 33

• 2 ≤ n < 3

• 3.7 ≤ n < 3

• 5.4 ≤ n < 6.4

• 4 ≤ n < 3

2x + 9 < 7 or -5x + 7 < -8

• x < -1 or x > 3

• x < 8 or x > 3

• x < -1 and x > 3

• x < 8 and x > 3

| 2x + 12 | < 8
Which is the correct first step?

• 2x + 12 < 8 and 2x+12 >-8
• 2x + 12 < 8 or 2x+12 >-8
• 2x + 12 < 8 and 2x+12 <-8
• 2x + 12 < 8 or 2x+12 >-8

| x - 6 | < 4
Is this an "and"  or an "or" problem?

• and
• or

What kind of compound inequality is this?

• AND compound inequality
• OR compound inequality

Solve:  -3 ≤ 2x - 1 ≤ 5

• -1 ≤ x ≤ 3
• -1 < x < 3
• 1 < x < 3
• 1 ≤ x ≤ 3