Kuiz Apersepsi Dalil Rantai Turunan Trigonometri

cos x

sin x

• - cos x

• - sin x

• - tan x

sin x

cos x

• - sin x

• - cos x

tan x

$$\frac{\text{d}x}{\text{d}y}=f'\left(x\right)=\sec\ x$$

$$\frac{\text{d}x}{\text{d}y}=f'\left(x\right)=\operatorname{cosec}\ x$$

$$\frac{\text{d}x}{\text{d}y}=f'\left(x\right)=\sec^2x$$

$$\frac{\text{d}x}{\text{d}y}=f'\left(x\right)=\operatorname{cosec}^2\ x$$

$$\frac{\text{d}x}{\text{d}y}=f'\left(x\right)=\operatorname{cotan}^2\ x$$

$$x^{n+1}$$

$$nx^{n+1}$$

$$nx^{n+1}$$

$$nx^{n-1}$$

$$\left(n-1\right)x^{n-1}$$

$$4x^3$$

$$3x^3$$

$$x^3$$

$$\frac{1}{4}x^3$$

$$\frac{1}{3}x^3$$

$$-6x^{-6}$$

$$-7x^{-6}$$

$$x^{-8}$$

$$-7x^{-7}$$

$$-7x^{-8}$$

$$\frac{\text{d}y}{\text{d}x}=3\cos x$$

$$\frac{\text{d}y}{\text{d}x}=\cos3x$$

$$\frac{\text{d}y}{\text{d}x}=3\sin3x$$

$$\frac{\text{d}y}{\text{d}x}=3\cos3x$$

$$\frac{\text{d}y}{\text{d}x}=-3\cos3x$$

$$-\frac{1}{2}\cos\ \frac{1}{2}x$$

$$-\frac{1}{2}\sin\ \frac{1}{2}x$$

$$\frac{1}{2}\sin\ \frac{1}{2}x$$

$$\cos\ \frac{1}{2}x$$

$$\sin\ \frac{1}{2}x$$

$$\left(2x+\pi\right)\cos\left(2x+\pi\right)$$

$$2\cos\left(2x+\pi\right)$$

$$-2\sin\left(2x+\pi\right)$$

$$-\left(2x+\pi\right)\sin\left(2x+\pi\right)$$

$$-2\cos\left(2x+\pi\right)$$

$$f'\left(x\right)=2x\cos x^2$$

$$f'\left(x\right)=-2x\cos x^2$$

$$x^2\sin x^2$$

$$f'\left(x\right)=2x\sin x^2$$

$$f'\left(x\right)=-2x\ \sin\ x^2$$