BS TEST2

Determine the output of the C code mentioned below:

#include <stdio.h>

int main()

{

float q = ‘a’;

printf(“%f”, q);

return 0;

}

• run time error

• a

• 97.000000

• d. a.0000000

Which of these is NOT a relational or logical operator

• =

• ||

• ==

• !=

What will be the output of the following C code?

#include<stdio.h>

int main()

{

int p = 1, q = 2, r = 3, s = 4, x;

e = r + s = q * p;

printf(“%d, %d\n”, x, s);

}

• Syntax error

• 5, 2

• 7, 2

• 7, 4

We cannot use the keyword ‘break’ simply within _________

• while

• for

• if-else

• do-while

The correct format of declaring a function is:

• type_of_return name_of_function (argument type);

• type_of_return name_of_function (argument type){}

• type_of_return (argument type) name_of_function;

• all of the above

Comment on the C statement given below:

int (*p)[5];

• A ragged array

• An array “p” of pointers

• A pointer “p” to an array

• None of the above

The output of the C code mentioned below would be:

#include <stdio.h>

struct employee

{

int id;

char rank[5];

}

void main()

{

struct employee e;

s.no = 30;

printf(“howdy”);

}

• hello

• Compile-time error

• 5, 30

• Varies

#include <stdio.h>

intmain()

{

    int i = 3;

    printf("%d", (++i)++);

    return 0;

}

What is the output of the above program?

• 3

    

• 4

• 5

• Compile-time error

What is short int in C programming?

• The basic data type of C
  

• Qualifier
  

• Short is the qualifier and int is the basic data type
  

• All of the mentioned

What will be the output of the following C function?

 

    #include <stdio.h>

enum birds {SPARROW, PEACOCK, PARROT};

enum animals {TIGER = 8, LION, RABBIT, ZEBRA};

    int main()

    {

enum birds m = TIGER;

        int k;

        k = m;

printf("%d\n", k);

        return 0;

}

• 0
  

• Compile time error
  

• 1
  

• 8