Lý GK I

Lệch pha một lượng $$\frac{\pi}{4}$$

$$T=2\pi\sqrt[]{\frac{l}{g}}$$

$$T=2\pi\sqrt[]{\frac{g}{l}}$$

$$T=\sqrt[]{\frac{g}{l}}$$

$$T=\sqrt[]{\frac{l}{g}}$$

$$s=s_0\cos\left(\frac{\omega}{t^2}+\varphi\right).$$

$$s=s_0\cos\left(\frac{\omega}{t}+\varphi\right)$$

$$s=s_0\cos(\omega t+\varphi).$$

$$s=s_0\cos(\omega t^2+\varphi)$$