Python comprehensions, generators, and exceptions

The code to the left can be written more compactly as

• a = 'hi' if x = 3 else 'there'

• a = if x == 3: 'hi' else: 'there'

• a = 'hi' if x == 3 else 'there'

The code to the left can be written more compactly as

• b = line if ('H' in line) else ''

• b = line if 'H' in line

• b = if 'H' in line: line else: ''

What is the result of the following statement?

print([i.upper() for i in "hello"])

• [‘H’, ‘E’, ‘L’, ‘L’, ‘O’]

• ‘HELLO’

• [‘HELLO’]

• HELLO

What datatype is x after the following statements?

a = [1, 2, 3]

x = [2*i for i in a]

• list

• tuple

• dictionary

• generator

What datatype is x after the following statements?

a = ['hello', 3.14, 7]

x = {i: 10 for i in a}

• list

• tuple

• dictionary

• generator

What is the result of the following statement?

print([i if i%2==0 else i+1 for i in range(4)])

• [0, 2, 2, 4]

• [1, 1, 3, 3]

• error

• none of the mentioned

Which list comprehension will pick out only negative integers from a given list ‘a’?

• [x<0 in a]

• [x for x<0 in a]

• [x in a for x<0]

• [x for x in a if x<0]

Which list comprehension will will result in a list with the value [‘e’, ‘o’] after the following lines are executed?

w="hello"

v=('a', 'e', 'i', 'o', 'u')

• [x for w in v if x in v]

• [x for x in w if x in v]

• [x for x in v if w in v]

• [x for v in w for x in w]

Which comprehension produces a list of numbers between 1 and 1000 that are divisible by 3.

• [x in range(1, 1000) if x%3==0]

• [x for x in range(1000) if x%3==0]

• [x%3 for x in range(1, 1000)]

• [x%3=0 for x in range(1, 1000)]

What will be printed?

• ('a', 1)

  ('b', 2)

  ('c', 3)

• a

  b

  c

• 1

  2

  3

• {'a': 1}

  {'b': 2}

  {'c': 3}