Quadratic Equations

Solve the equation 2x^2 + 7x + 1 = 0 using the quadratic formula.

• x = (-7 + √41) / 8 and x = (-7 - √41) / 8

• x = (-7 + √41) / 2 and x = (-7 - √41) / 2

• x = (-7 + √41) / 4 and x = (-7 - √41) / 4

• x = (-7 + √41) / 4 and x = (-7 - √41) / 4

What is the quadratic formula used to solve quadratic equations?

• x = (-b ± √(b^2 - 4ac)) / (2a)

• x = (-b ± √(b^2 + 4ac)) / (2a)

• x = (-b ± √(b^2 + 4ac)) / (a)

• x = (-b ± √(b^2 - 4ac)) / a

What are the coefficients of the quadratic equation 2x^2 + 7x + 1 = 0?

• 2, 7, 0

• 2, 7, -1

• 2, 6, 1

• 2, 7, 1

Calculate the discriminant of the equation 2x^2 + 7x + 1 = 0.

• -41

• 41

• 0

• 1

Find the solutions for the equation 2x^2 + 7x + 1 = 0 using the quadratic formula.

• x = (-7 + √41) / 8 and x = (-7 - √41) / 8

• x = (-7 + √41) / 2 and x = (-7 - √41) / 2

• x = (-7 + √41) / 4 and x = (-7 - √41) / 4

• x = (-7 + √41) / 4 and x = (-7 - √41) / 4