Quiz about angulo doble

Question 1

Halle: H = sen 2x

Accepted Answer

-4/5

Answer

4/5

Answer

-2/5

Answer

-3/5

Question 2

Reducir

Accepted Answer

2cosx

Answer

2senx

Answer

senxcox

Answer

-2cosx

Question 3

Question 3.

Accepted Answer

1/2

Answer

1/3

Answer

1/4

Answer

1/5

Question 4

Question 4.

Accepted Answer

COS2X

Answer

SEN2X

Answer

TAN2X

Answer

COT2X

Question 5

Question 5.

Accepted Answer

5/13

Answer

2/13

Answer

3/13

Answer

4/13

Question 6

$$Reducir:\ \ \ \ H=\cos^4x\ -\ sen^4x\ \ \ \ $$

Accepted Answer

cos2x

Answer

sen2x

Answer

cos4x

Question 7

Si senx=1/2. Halla: sen3x

Accepted Answer

1

Answer

1/8

Answer

3/2

Question 8

$$Sea:\ \cos x=\sqrt{\frac{1}{3}};_{\ x\ agudo\ \ Hallar:\ \ an3x}$$

Accepted Answer

$$-\frac{\sqrt{2}}{5}$$

Answer

$$-\frac{5}{11}$$

Answer

$$\frac{\sqrt{3}}{5}$$

Question 9

Si Tanx = 3/4 entoces Tan2x es:

Accepted Answer

24/7

Answer

12/5

Answer

27/7

Answer

1/7

Question 10

Si Senx=1, entonces Sen2x

Accepted Answer

0

Answer

1

Answer

-1

Answer

2

Question 11

$$Calcular:$$
$$M=\frac{1- an^222°30´}{2 an22°30´}$$

Accepted Answer

1

Answer

2

Answer

3

Answer

4

Question 12

Podemos cambiar a $$Senx.Cosx$$ Por:

Accepted Answer

$$\frac{Sen2x}{2}$$

Answer

$$Sen2x$$

Answer

$$Sen^2x$$

Answer

$$2Senx$$

Question 13

El Equivalente de $$\ \ 1- an^2x\ \ $$ es:

Accepted Answer

$$\frac{2Tanx}{Tan2x}$$

Answer

$$Sec^2x$$

Answer

$$-Sec^2x$$

Answer

$$\frac{Tan2x}{2Tanx}$$

Question 14

Equivale a la $$ an\frac{x}{2}\ $$ :

Accepted Answer

$$\sqrt{\frac{1-Cosx}{1+Cosx}}$$

Answer

$$\sqrt{\frac{1+Cosx}{1-Cosx}}$$

Answer

$$Cscx\ -\ Cotx$$

Answer

$$1-Tan^2x$$

Question 15

$$A\ que\ es\ igual:\ Cscx\ -Cotx$$

Accepted Answer

$$Tan\frac{x}{2}$$

Answer

$$Cot\ \frac{x}{2}$$

Answer

$$Tan2x$$

Answer

$$Cot2x$$

Question 16

$$1\ +\ Cosx$$ Se puede escribir como:

Accepted Answer

$$2Cos^2\frac{x}{2}$$

Answer

$$2Sen\frac{x}{2}$$

Answer

$$2Cos\frac{x}{2}$$

Answer

$$2Sen^2\frac{x}{2}$$

Question 17

Question 17.

Accepted Answer

D

Answer

A

Answer

B

Answer

C

Answer

E

Question 18

Question 18.

Accepted Answer

B

Answer

A

Answer

C

Answer

D

Answer

E

Question 19

Accepted Answer

Ib, IIc, IIIa, IVd

Answer

Ia, IIb, IIIc, IVd

Answer

Ib, IIa, IIIc, IVd

Answer

Ib, IIc, IIId, IVa

Question 20

Halle: H = sen 2x

Accepted Answer

-4/5

Answer

4/5

Answer

3/5

Answer

5/6

Question 21

Si $$\alpha$$ es un angulo agudo, tal que tan $$\alpha$$ = $$\frac{1}{5}$$ . Calcular el valor de sen $$\alpha$$ .

Accepted Answer

$$\frac{1}{\sqrt{26}}$$

Answer

$$\frac{1}{26}$$

Answer

$$\sqrt{26}$$

Answer

$$\frac{1}{\sqrt{13}}$$

Question 22

Si senx+cosx= $$\frac{\sqrt{2}}{2}$$ , calcular sen2x.

Accepted Answer

-1/2

Answer

1/3

Answer

-1/5

Answer

1/6

Question 23

LA ECCUACION DE SEN2X ES :

Accepted Answer

2SENX.COSX

Answer

SENX.COSX

Answer

3SENX.COSX

Answer

2TGX.SENX

Question 24

MENCIONA EL DESARROLLO DE SEN4X

Accepted Answer

2SEN2X.COS2X

Answer

2SENX.COSX

Answer

4SEN2X.COX2X

Answer

3SEN2X.COSX

Question 25

EL VALOR DE SEN6X SERIA IGUAL A

Accepted Answer

2SEN3X.COS3X

Answer

4SEN2X.COSX

Answer

4SENX.COSX

Answer

2SEN2X.COX2X

Question 26

Si cotx- tanx = 8, entonces calcular el valor de:

A=2cot2x

Accepted Answer

8

Answer

4

Answer

-4

Answer

-8

Question 27

Podemos cambiar a $$Senx.Cosx$$ Por:

Accepted Answer

$$\frac{Sen2x}{2}$$

Answer

$$Sen2x$$

Answer

$$Sen^2x$$

Answer

$$2Senx$$

Question 28

$$A\ que\ es\ igual:\ Cscx\ -Cotx$$

Accepted Answer

$$Tan\frac{x}{2}$$

Answer

$$Cot\ \frac{x}{2}$$

Answer

$$Tan2x$$

Answer

$$Cot2x$$

Question 29

Question 29.

Accepted Answer

$$\frac{\sqrt{3}}{3}$$

Answer

1/3

Answer

$$\frac{\sqrt{6}}{2}$$

Answer

$$\frac{3}{\sqrt{3}}$$

Answer

2/5

Question 30

Question 30.

Accepted Answer

$$\frac{3\sqrt{5}}{10}$$

Answer

1

Answer

2

Answer

$$\frac{\sqrt{2}}{3}$$

Answer

$$\frac{3\sqrt{7}}{5}$$

Question 31

Question 31.

Accepted Answer

$$\sqrt{0,6}$$

Answer

$$\sqrt{0,5}$$

Answer

$$\sqrt{0,7}$$

Answer

$$\sqrt{0,8}$$

Answer

$$\sqrt{0,9}$$

Question 32

Question 32.

Accepted Answer

$$\sqrt{\frac{5}{12}}$$

Answer

$$\sqrt{\frac{5}{6}}$$

Answer

$$\sqrt{\frac{1}{6}}$$

Answer

$$\sqrt{\frac{1}{12}}$$

Answer

$$\sqrt{\frac{7}{12}}$$

Question 33

Question 33.

Accepted Answer

4

Answer

2

Answer

3

Answer

5

Answer

6

Question 34

Question 34.

Accepted Answer

$$\frac{1}{2}$$

Answer

3

Answer

$$\frac{2}{5}$$

Answer

$$\frac{1}{7}$$

Answer

5

Question 35

Question 35.

Accepted Answer

$$-\frac{2}{3}$$

Answer

$$\frac{1}{5}$$

Answer

$$-\frac{3}{2}$$

Answer

$$\frac{4}{3}$$

Answer

$$-\frac{3}{4}$$

Question 36

Question 36.

Accepted Answer

4

Answer

2

Answer

3

Answer

5

Answer

6

Question 37

Question 37.

Accepted Answer

-2senx

Answer

2senx

Answer

-2 cosx

Answer

2 cosx

Answer

senx

Question 38

El valor de "Sen2x" es igual a:

Accepted Answer

2Senx.Cosx

Answer

2Tanx.Cosx

Answer

4Senx.Cosx

Answer

$$Cos^2x\ -\ Sen^2x$$

Question 39

A que es igual "Cos2x"

Accepted Answer

$$Cos^2x\ -\ Sen^2x$$

Answer

$$Cos^2x\ +\ Sen^2x$$

Answer

$$\frac{Senx}{Cosx}$$

Answer

$$2Senx.Cosx$$

Question 40

Reduce: $$M=\ Tan2x.\ \frac{1-Tan^2x}{Tanx}$$

Accepted Answer

2

Answer

1

Answer

1/2

Answer

1/4

Question 41

Reduce: M = Sen2x.Secx.Cscx

Accepted Answer

2

Answer

senx

Answer

cosx

Answer

1

Question 42

Accepted Answer

4/5

Answer

1/5

Answer

2/5

Answer

3/5

Answer

2/3

Question 43

Accepted Answer

-5/13

Answer

-4/13

Answer

-6/13

Answer

-7/13

Answer

-9/13

Question 44

Accepted Answer

2

Answer

1

Answer

1/2

Answer

1/3

Answer

3

Question 45

Accepted Answer

2

Answer

1/2

Answer

1

Answer

3/2

Answer

2/3

Question 46

Si la tgx = 4 (x es agudo)

Calcular: Cos2x

Accepted Answer

-15/17

Answer

12

Answer

34

Answer

16

Question 47

Si la tgx = 0.33333.... (x es agudo)

Calcular: Cos2x

Accepted Answer

4/5

Answer

78

Answer

4/8

Answer

7/9

Question 48

Si $$\alpha$$ es un angulo agudo, tal que cos $$\alpha$$ = $$\frac{1}{5}$$ . Calcular el valor de: cos 2 $$\alpha$$ .

Accepted Answer

-23/25

Answer

-23/24

Answer

-22/25

Answer

-21/25

Question 49

$$\frac{sen^2x}{\cos^2x}$$

Accepted Answer

$$	an^2x$$

Answer

1

Answer

12

Answer

11

Question 50

REDUCE

E= (Senx + Cosx)² - 1

Accepted Answer

Sen2x

Answer

Senx

Answer

Cos2x

Answer

1

Question 51

REDUCIR:

$$B\ =\ \left(\frac{Sen2x}{Cosx}\right)^2\ +\ \ \left(\frac{Sen2x}{Senx}\right)^2$$

Accepted Answer

4

Answer

2

Answer

3

Answer

5

Question 52

EL CATETO OPUESTO ES.

Accepted Answer

OPUESTO AL ANGULO QUE VOY ENCONTRAR

Answer

ADYACENTE AL ANGULO QUE VOY ENCONTRAR

Answer

ANGULO AGUDO

Answer

ANGULO RECTO

Question 53

Si $$\cos\alpha=\frac{1}{2}$$ , entonces $$\sec\alpha=?$$

Accepted Answer

$$2$$

Answer

$$\frac{3}{\sqrt[]{3}}$$

Answer

$$\frac{3}{5}$$

Answer

$$\frac{5}{\sqrt[]{3}}$$

Question 54

Si $$tg\ \beta=\frac{3}{5}$$ , entonces $$\sec\beta=?$$

Accepted Answer

$$\frac{\sqrt[]{34}}{5}$$

Answer

$$\frac{4}{5}$$

Answer

$$\frac{5}{4}$$

Answer

$$\frac{5\sqrt[]{34}}{34}$$

Question 55

Determina $$\cos\ A,\ si\ \sec A=\frac{10}{3}$$

Accepted Answer

$$\frac{3}{10}$$

Answer

$$\frac{4}{10}$$

Answer

$$\frac{10}{4}$$

Answer

$$\frac{4}{3}$$

Question 56

Determina el valor de R, si:

$$R=\left(a+b\right)^2.sen^490\degree+\left(a-b\right)^2.\cos^3180\degree$$

Accepted Answer

$$4ab$$

Answer

$$2\left(a^2+b^2\right)$$

Answer

$$-4ab$$

Answer

$$2\left(a^2-b^2\right)$$

Question 57

$$tg\ 1837^0$$ es:

Accepted Answer

$$\frac{3}{4}$$

Answer

$$\frac{3}{5}$$

Answer

$$\frac{4}{3}$$

Answer

$$\frac{5}{3}$$

Question 58

$$\sec\ 2017^0$$

Accepted Answer

$$\frac{-5}{4}$$

Answer

$$\frac{5}{4}$$

Answer

$$\frac{-3}{5}$$

Answer

$$\frac{3}{5}$$

Question 59

$$\operatorname{ctg}\ 225^0$$ es

Accepted Answer

1

Answer

$$\sqrt[]{2}$$

Answer

-1

Answer

$$\frac{\sqrt[]{2}}{2}$$

Question 60

$$\csc\ 323^0$$ es

Accepted Answer

$$\frac{5}{4}$$

Answer

$$\frac{3}{5}$$

Answer

$$\frac{5}{3}$$

Answer

$$\frac{4}{5}$$

Question 61

$$tg1800^0$$ es

Accepted Answer

0

Answer

-1

Answer

1

Answer

nd

Question 62

$$Csc\ 2070^0$$ es

Accepted Answer

-1

Answer

nd

Answer

1

Answer

0

Question 63

Simplificar M = $$\left(Tg\alpha\ +\ Ctg\alpha\right)Cos\alpha Sen\alpha$$

Accepted Answer

1

Answer

tg

Answer

-1

Answer

sec

Question 64

$$\ \ Simplificar\ \ \ \ M\ =\ \ \ Sec\alpha.\cos\alpha$$

Accepted Answer

1

Answer

-1

Answer

0

Answer

ctg

angulo doble

146 questions

Si: tanx=2/5 (x es ángulo agudo) ) calcular: sen2b

calcular: cos2θ

Reducir:
M = sen2x.secx – senx

Reducir:

Reducir la siguiente expresión:

Reducir la siguiente expresión

Reducir la siguiente expresión:

Señale el equivalente de:
M=senx.cosx.cos2x

Señale el equivalente de:
M=4senx.cosx.cos2x.cos4x.cos8x

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angulo doble

146 questions

Si: tanx=2/5 (x es ángulo agudo) ) calcular: sen2b

calcular: cos2θ

Reducir:M = sen2x.secx – senx

Reducir:

Reducir la siguiente expresión:

Reducir la siguiente expresión

Reducir la siguiente expresión:

Señale el equivalente de:M=senx.cosx.cos2x

Señale el equivalente de:M=4senx.cosx.cos2x.cos4x.cos8x

Create a free account and access millions of resources

Similar Resources on Wayground

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Discover more resources for Mathematics

Reducir:
M = sen2x.secx – senx

Señale el equivalente de:
M=senx.cosx.cos2x

Señale el equivalente de:
M=4senx.cosx.cos2x.cos4x.cos8x