11/14 Exit ticket Solving quadratics/ domain and range

Solve
a² + 2a - 24 = 0

• a = -6, 4
• a = 6, -4
• a = 12, -2
• a = 8, -3

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

Solve
4m² - 100 = 0

• m=25, -25

• m=96

• m=5, -5

• m=-96

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

CCSS.HSA.CED.A.1

What are the zeros?

• x= 0 and x= -4
• x= 0 and x= 4
• y= 0
• x= 2

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

CCSS.HSA.APR.B.2

True or false:
The solutions, roots, x-intercepts, and zeros of a quadratic equation are all the same thing.

• True
• False, because the solution and root are the same but the x-intercept and zero are different
• False, because the x-intercept and root are the same but the zero and solution are different
• False, they are all different

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

Find the zeros of the equation: 
(x+10)(x-2) = 0

• 10 and 2
• -2 and 10
• -10 and 2
• -2 and -10

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

Solve using Zero-Product Property
(x-11)(5x+1) = 0

• x = 11 or x = -1/5
• x = -11 or x = -1/5
• x = 11 or x = 1/5
• x = -11 or x = 1/5

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

What are the solutions/zeros/x-intercepts/roots?

(When does this quadratic =0?)

SELECT ALL THAT APPLY

• x = -4

• x = -1

• x = 0

• x = 2

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

CCSS.HSA.REI.D.11

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

Solve by factoring!

• -2, 4

• -8

• ±8

• No real solution

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2

What are the zeros?

• x= 0 and x= -4
• x= 0 and x= 4
• y= 0
• x= 2

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.APR.B.3