
Unit 9: Problem Solving: Boyle's/Charles'
Authored by Alison Klein
Chemistry
11th Grade
Used 5+ times

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12 questions
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1.
MATCH QUESTION
1 min • 1 pt
A balloon filled with helium occupies a volue of 1.50L at 752 torr and 25oC. What will be the volume of the balloon at a pressure of 438 torr if there is no change in temperature?
752 torr
Volume 2= V2
1.50L
Pressure 2= P2
438 torr
Volume 1= V1
This is what we are solving for.
Pressure 1= P1
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A balloon filled with helium occupies a volue of 1.50L at 752 torr and 25oC. What will be the volume of the balloon at a pressure of 438 torr if there is no change in temperature?
3.
MATCH QUESTION
1 min • 1 pt
In a typical automobile, the mixture of gasoline and air in a cylinder is compressed from 1.0 atom to 9.5 atm. If the uncompressed volume of the cylinder is 410 mL, what is the volume in mL when the mixture is fully compressed?
This is what we are solving for.
Pressure 2= P2
410mL
Volume 2= V2
9.5 atm
Pressure 1= P1
1.0 atm
Volume 1= V1
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In a typical automobile, the mixture of gasoline and air in a cylinder is compressed from 1.0 atom to 9.5 atm. If the uncompressed volume of the cylinder is 410 mL, what is the volume in mL when the mixture is fully compressed?
5.
MATCH QUESTION
1 min • 1 pt
A gas has a volume of 37.5mL at a pressure of 95 kPa. If the new pressure is standard pressure, what is the new volume?
Hint: Standard pressure is the pressure that is equal to 1 atm.
This is what we are solving for.
Pressure 2= P2
101.3 kPa
Volume 1= V1
37.5mL
Volume 2= V2
95 kPa
Pressure 1= P1
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A gas has a volume of 37.5mL at a pressure of 95 kPa. If the new pressure is standard pressure, what is the new volume?
Hint: Standard pressure is the pressure that is equal to 1 atm.
7.
MATCH QUESTION
1 min • 1 pt
Oxygen gas is commonly sold in 49.0L steel containers at a pressure of 150atm. What volume in liters would the gas occupy at a pressure of 1.02 atm if its temperature remained unchanged?
1.02 atm
Volume 1= V1
This is what we are solving for.
Pressure 2= P2
49.0L
Volume 2= V2
150atm
Pressure 1= P1
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