Unit 5 Quadratics Review

Find the y-intercept of f(x) = 2x² - 2x + 1

• 2
• -2
• 1
• -1

Tags

CCSS.HSF-IF.C.7A

What's the vertex of
 y = -2(x - 3)² + 1? 

• (1, 3)
• (-3, 1)
• (9, 1)
• (3, 1)

Solve by completing the square.
x² - 2x - 5 = 0

• x = 1 ± √6
• x = 3 and -1
• x = -1 ± √6
• x = 1 and -3

Tags

CCSS.HSA-REI.B.4B

Convert to vertex form.

• y=3(x+1)² - 8
• y=3(x-1) ² - 8
• y=3(x+2)² - 8
• y=3(x-2)² - 8

Convert to vertex form:

y = x² + 4x + 10

• y = (x + 4)² + 6

• y = (x + 2)² + 6

• y = (x + 4)² - 6

• y = (x + 2)² - 6

Solve by completing the square.
x² +12x = 5

• X = 6 + √41 or  6 − √41
• X= 35 or 47
• X = −6 + √41 or  −6 − √41
• X = √35 or √47

Tags

CCSS.HSA-REI.B.4B

• No real solution

Tags

CCSS.HSA-REI.B.4B

Use the discriminant to determine the number of solutions the following quadratic equation has.

6x² − 2x − 3 = 0

• 76 Two Real Solutions

• 29 Two Non Real Solutions

• 68 One Solution

• none of these

Tags

CCSS.HSA-REI.B.4B

Use the discriminant to determine the number of solutions the following quadratic equation has.

-2x² − x − 1 = 0

• 76 Two Solutions

• -7 Two Non Real Solutions

• 9 Two Solutions

• 0 One Solution

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7