Module 3: Operations with Integers Review

Which pairs of integers are additive inverses? Select all that apply.

• -28 and 28

• 4 and 4

• -495 and -495

• -3 and 3

• 1800 and -1800

Tags

CCSS.7.NS.A.1B

Complete the following sentence to show how to use absolute value to find 7 + (-15).

The difference in the absolute value of the integers is _____.

• -8

• 8

• 22

• -22

Tags

CCSS.7.NS.A.1B

• Positive

• Negative

Tags

CCSS.7.NS.A.1B

Therefore, 7 + (-15) =

• -8

• 8

• -22

• 22

Tags

CCSS.7.NS.A.1C

The table shows most recent transactions in Ralph's bank account. Ralph's bank account total after the transactions is ____.

Tags

CCSS.7.NS.A.3

What properties could you have used to solve Ralph's bank account total after the transactions? Select all the apply.

• Commutative Property of Addition

• Commutative Property of Multiplication

• Associative Property of Addition

• Multiplicative Identity Property

• Distributive Property

Tags

CCSS.7.NS.A.1D

What number sentence is modeled by the vertical number line?

• -4 + -8 = -8

• -4 + 4 = 8

• -4 + (-4) = 8

• -4 + 4 = -8

• -4 + (-4) = -8

Tags

CCSS.7.NS.A.1B

Find -13 - (-19) =

• 6

• -6

• 32

• -32

Tags

CCSS.7.NS.A.1C

Evaluate w – d if d = –2 and w = 3.

Tags

CCSS.6.EE.A.2C

Describe how to use absolute value to find the distance between -10 and 5 on a number line. Then use this method to determine the distance between the integers.

• You subtract the two integers (-10 - 5 = -15), then take the absolute value of -15, which is 15. So the distance is 15.

• You subtract the two integers (-10 - 5 = -15), so the distance is -15.

• You add the two integers (-10 + 5 = -5), then take the absolute value of -5, which is 5. So the distance is 5.

• You add the two integers (-10 + 5 = -5), so the distance is -5.

Tags

CCSS.7.NS.A.1C