A1 Semester 1 Final Review

-15 = 5a +12- 2a + 6

• -11
• -3
• 10
• 7

3a + 9 + 4a = 2

• -1
• 1
• no solution
• -7

What is the first step in solving the equation 2a - 4(a - 5) = 10

• Add 4 to both sides
• Add the 2a and a 
• Distribute 4 to a and -5
• Distribute -4 to a and -5

8 = (³⁄₄)a +12 - a + 4

• 32
• -6
• -4
• 4

4(a + 3) = -32

• -11
• -44
• -20
• -8

2 + 14a = -8 + 9a

• -2
• 3
• 5
• -10

-a = 9(a - 10)

• 9
• 1
• 90
• 10

22 + 2a = 37 + 6 + a

• 21
• -21
• 5
• 6

Identify if this equation has one solution, infinitely many solutions or no solution.
-3x+1=x+9-4x

• one solution
• infinitely many
• no solution

Solve:
6x+10>5x-12

• x>2
• x<2
• x<-22
• x>-22