Throwback Thursday Quiz #4

Throwback Thursday Quiz #4

11th Grade

6 Qs

quiz-placeholder

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Throwback Thursday Quiz #4

Throwback Thursday Quiz #4

Assessment

Quiz

Chemistry

11th Grade

Medium

Created by

Jennifer Cambre

Used 4+ times

FREE Resource

6 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Because two molecules of NO are consumed per molecule of O2, the rate of disappearance of O2(g) is 2.5 x 10-5 Ms-1.

Because two molecules of NO are consumed per molecule of O2, the rate of disappearance of O2(g) is 1.0 x 10-4 Ms-1.

Because the rate depends on [NO]2 and [O2], the rate of disappearance of O2(g) is 2.5 x 10-9 Ms-1.

Because the O2(g) is under the same experimental conditions as NO, it is consumed at the same rate of 5.0 x 10-5 Ms-1.

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The rate of reaction will remain the same, because k will decrease by half.

The rate of reaction will double, because the rate is directly proportional to [S2O82-].

The rate of reaction will increase by a factor of four, because two moles of SO42- are produced for each mole of S2O82- consumed.

The rate of reaction will increase by a factor of four, because the reaction is second order overall.

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Rate = k

Rate = k[HO2]

Rate = k[HO2]2

Rate = k[H2O2][O2]

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

P1/9

P1/3

P1

3P1

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Equal volumes of 0.2 M solutions of lead(II) nitrate and potassium bromide are combined to form lead(II) bromide as a yellow precipitate. Which of the following is the correct net ionic equation for the reaction?

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

To gravimetrically analyze the silver content of a piece of jewelry made from an alloy of Ag and Cu, a student dissolves a small preweighed sample in HNO3(aq). Ag+(aq) and Cu2+(aq) ions form in the solution. Which of the following should be the next step in the analytical process?

Centrifuging the solution to isolate the heavier ions

Evaporating the solution to recover the dissolved nitrates

Adding enough base solution to bring the pH up to 7.0

Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions