Solve Equations

12x = 144

4a + 3 = 15

Which equation has x = 2 as a solution?

• 3 + x = 10
• 11 + x = 13
• 4x = 32
• 5x =25

y + 8 = 20

k - 10 = 7

3p - 1 = 5

27 = 5r + 2

2(u - 9) = 4

• 10
• 11
• 12
• 13

15 + 4a - 6 = 21

• 1
• 2
• 3
• 4

Simplify:
5(3x+1)