Solving Quadratics part 1 (ch 3.1)

Solve for x: √(x+5) = 7

• x = 15

• x = 10

• x = 44

• x = 2

Find the value of x: √(3x+4) = 10

• x = 3

• x = 10

• x = 7

• x = 32

Solve the equation: √(5x+2) = 12

• x = 142/5

• x = 5

• x = -14

• x = 8

Solve for x: √(7x+8) = 20

• x = 15

• x = 10

• x = 56

• x = 25

Determine the value of x: √(9x+12) = 30

• x = 12

• x = 888

• x = 888/9

• x = 15

Solve the equation: √(10x-13) = 35

• There is no solution in the real number system.

• x = 123.8

• x = 1225

• x = 1238

Solve
4m² - 100 = 0

• m=25, -25
• m=96
• m=5, -5
• m=-96

Solve
9x² - 81 = 0

• x=3, -3

• x=9

• x=-9

• x=81, -81

Convert x²-9x+20 to factored form and solve.

• (x-10)(x+2); x=-2, 10
• (x+4)(x+5); x=-5, -4
• (x-4)(x-5); x=4, 5
• Not factorable

What are the zeros?

• x= 0 and x= -4
• x= 0 and x= 4
• y= 0
• x= 2