Circle Equations & Completing the Square

• 8

• 4

• -16

• 16

Tags

CCSS.HSA.APR.B.2

• 22

• 11

• 121

• 44

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Solve by completing the square.
y² + 10y = -9

• 1 and -12
• -1 and -9
• 1 and -9
• 1 and -1

Tags

CCSS.HSA-REI.B.4B

Convert the to standard form. x² + y² + 6x - 10y - 15 = 0

• (x + 6)² + (y - 10)² = 225

• (x + 3)² + (y - 5)² = 361

• (x + 3)² + (y - 5)² = 7

• (x + 3)² + (y - 5)² = 49

Tags

CCSS.HSG.GPE.A.1

What is the center and radius given the equation, x² + y² + 8x - 2y - 64 = 0?

• Center: (-4, 1), Radius: 9

• Center: (4,1), Radius: 8

• Center: (1,-4), Radius: 64

• Center: (-4, 1), Radius: 81

Tags

CCSS.HSG.GPE.A.1

Tags

CCSS.HSG.GPE.A.1

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x-3)² + (y+6)² = 25
• (x+3)² + (y-6)² = 25
• (x-3)² + (y+6)² = 45
• (x+3)² + (y-6)² = 5

Tags

CCSS.HSG.GPE.A.1

A circle has the equation  x² + y² - 12x + 8y + 3 = 0.  Use completing the square to write the equation in standard form.

• (x - 6)² + (y + 4)² = 49
• (x + 4)² + (y - 6)² = 49
• (x - 6)² + (y + 4)² = 55
• x² + y² = 55

Tags

CCSS.HSG.GPE.A.1