Exam Unit 8 - Part A - Describing Quadratic Functions

The function f(x) = x² was transformed to create the function (g(x) = f(x + 3) + 5.

Choose the correct answer from each drop-down menu to complete the statement. The graph of f is translated 3 units ​ (a)   and 5 units ​ (b)   to create the graph of g.

• down

• right

• left
• up

Which statement describes what happens to the graph of y = x²

if the equation is changed to y = 3x² - 2 ?

• The graph's vertex is now located at (0, -2).

• The graph's vertex is now located at (3, -2).

• The graph's vertex moves two units to the left.

• The graph's vertex moves up two units on the y-axis.

The graph of f(x) = x² is reflected over the x-axis and is stretched horizontally to create the graph of function g.

Which graph could represent g?

• 
• 
• 
• 

A quadratic function has a vertex point of (3, 1) and passes through the point (6, –8).

Which equation represents the quadratic function?

• y = -x² + 6x - 8

• y = x² - 6x + 10

• y = -x² - 6x - 8

• y = -x² + 6x - 10

The graph of a quadratic function has vertex (1, 4) and passes through the point (3, -8).

What is the equation of the quadratic function?

• f(x) = -3(x - 1)² + 4

• f(x) = -3(x - 1)² - 4

• f(x) = -(x - 1)² - 4

• f(x) = -(x - 1)² + 4

Solve the following quadratic equation.

x² + 2x - 5 = 0 . Select TWO correct answers.

What is the solution set for

12x² - 40 = -17x ?

Given g(x) = x² – 6x – 16,

which statement is true?

• The zeros are -8 and 2, because the factors of g are (x + 8) and (x - 2).

• The zeros are -8 and -2, because the factors of g are (x + 8) and (x + 2).

• The zeros are -2 and 8, because the factors of g are (x + 2) and (x - 8).

• The zeros are 2 and 8, because the factors of g are (x - 2) and (x - 8).

The graph of a quadratic function is shown on the grid.

Which function is best represented by this graph?

The solutions to a quadratic equation are {-2, 7}.

Which equation can be used to represent the quadratic function?

• h(x) = x² + 5x - 14

• h(x) = -2x² + 7x

• h(x) = x² - 5x - 14

• h(x) = (x + 2)² + 7