
9-05: Titration
Authored by Theodor Fuqua
Chemistry
9th - 12th Grade
NGSS covered
Used 13+ times

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10 questions
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1.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
In a titration, 10.0 mL of 0.0750 M HCl(aq) is exactly neutralized by 30.0 mL of KOH(aq) of unknown concentration. What is the concentration of the KOH(aq) solution?
0.0250 M
0.0750 M
0.225 M
0.333 M
2.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Which volume of 0.600 M H2SO4(aq) exactly neutralizes 100. milliliters of 0.300 M Ba(OH)2(aq)?
25.0 mL
50.0 mL
100. mL
200. mL
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The laboratory process in which the volume of a solution of known concentration is used to determine the concentration of another solution is called
distillation
fermentation
titration
transmutation
Tags
NGSS.HS-PS1-5
4.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
What is the volume of 0.30 M NaOH(aq) needed to completely neutralize 15.0 milliliters of 0.80 M HCl(aq)?
3.6 mL
5.6 mL
20. mL
40. mL
Tags
NGSS.HS-PS1-7
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The data collected from a laboratory titration are used to calculate the
rate of a chemical reaction
heat of a chemical reaction
concentration of a solution
boiling point of a solution
6.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Base your answer to this question on the information below. In performing a titration, a student adds three drops of phenolphthalein to a flask containing 25.00 milliliters of HCl(aq). Using a buret, the student slowly adds 0.150 M NaOH(aq) to the flask until one drop causes the indicator to turn light pink. The student determines that a total volume of 20.20 milliliters of NaOH(aq) was used in this titration. Choose the correct numerical setup to calculate the molarity of the HCl(aq) used in this titration.
(MA)(20.20 mL) = (0.150 M)(25.00 mL)
(MA)(25.00 mL) = (0.150 M)(20.20 mL)M
(MA)(25.00 mL) = (0150 M)(20.20 mL)M
(MA)(0.150 mL) = (0.150 M)(20.20 mL)M
7.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Information related to a titration experiment is given in the balanced equation and table.
H2SO4(aq) + 2KOH(aq) → K2SO4(aq) + 2H2O(l)
0.12 M
0.16 M
0.24 M
0.96 M
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