CHEMISTRY

Calculate the number of individual nitrogen atoms in 151 g of ammonium azide, NH₄N₃

• 2.06 x 10²⁴ N

• 4.06 x 10²⁴ N

• 6.06 x 10²⁴ N

• 8.06 x 10²⁴ N

Calculate the volume of a 2.80 M solution that contains 4.00 mol of solute

• 1.43 L

• 2.43 L

• 3.43 L

• 4.43 L

How many moles of Mg are required to react with 3.50 mol of oxygen gas? The balanced equation is 2Mg(s) + O₂(g) ---> 2MgO(s)

• 1 mol MG

• 3 mol Mg

• 5 mol Mg

• 7 Mol Mg

Calculate the molarity of 1.50 L of a 2.50 M solution after it has been diluted to 4.50L

• 0. 0.833 M

• 0.633 M

• 0.433 M

• 0.233 M

Consider the formula of hydrazinium nitrate, N₂H₆(NO₃)₂. Calculate the number of individual nitrogen atoms in that quantity

• 1.65 x 10²³ N

• 2.65 x 10²³ N

• 3.65 x 10²³ N

• 4.65 x 10²³ N

Consider the formula hydrazinium nitrate, N₂H₆(NO₃)₂. Calculate its molar mass

• 158 g

• 258 g

• 358 g

• 458 g

Consider the formula of hydrazinium nitrate, N₂H₆(NO₃)₂. Calculate the number of moles of nitrogen atoms in that quantity of compound

• 0.440 mol N

• 0.122 mol N

• 0.321 mol N

• 0.123 mol N

Find the molarity of a solution containing 4.50 mmol of solute in 2.00 mL of solution

• 1.25 M

• 2.25 M

• 3.25 M

• 4.25 M

Calculate the number of moles of sodium required to react with 17.56 mol of liquid bromine. The balanced equation is 2Na + Br₂ ---> 2NaBr

• 15.12 mol Na

• 25.12 mol Na

• 35.12 mol Na

• 45.12 mol Na

Consider the equation 2Na + Cl₂ ---> 2NaCl. Calculate the quantity of sodium chloride that can be prepared by the reaction of 2 mol of sodium and 2 mol chlorine

• 1 mol

• 2 mol

• 1.5 mol

• 3 mol